according to the topic
5000+1400+1700+2200-5000×80%+1200
=55300-4000+1200
=$52500
Thus we choose option B
B.$52,500
Part A:
Express the given number of hours and velocities of the cyclist as ordered pairs. The time (number of hours) can be our abscissa (x-coordinate) and the velocities can be our ordinate (y-coordinate). The coordinates are therefore (2, 18) and (4, 4). The equation that can be formed in this is established through the two-point equation.
(y - y₁) = ((y₂ - y₁)/(x₂ - x₁))(x - x₁)
Substitute the known variables.
(y - 18) = ((4 - 18)/(4 - 2))(x - 2)
Simplifying the equation,
y - 18 = -7(x - 2)
y = -7x + 32
<em>ANSWER: y = -7x + 32
</em>Part B: This can be graph in the Cartesian plane and numbers 1 to 8 can be substituted to y and take note of the ordered pairs for each point. The slope of the line should be -7 and the y-intercept is 32.<em>
</em>
Recall the secant-tangent theorem, and you have
EA^2 = EC*CD
12^2 = 8*(x+10)
and now ED = EC+CD = 8+x+10
I suspect a typo somewhere in the murk above
Answer:
Given the statement:
8,000 earn in four years compounded daily at 5%
To find the amount we use formula:

where P is the principal , A is the amount , n is number of times compounded per year and t is the time in year.
Here, Principal(P) = $8000, r = 5% and n = 365
Substitute these given values we get;



Simplify:

To find the Interest we use formula:


It is also given that:
8,000 earn in four years compounded annually at 5%.
Here, P = $8000, r = 5% , t =4 year and n = 1
Using the same formula to calculate the amount:


Simplify:

To find the Interest :


Then;

Therefore, $47.23 more would $8,000 earn in four years compounded daily at 5% than compounded annually at 5%