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4 years ago

Well guys I just need help I go to Dixie elementary and I’m in fourth grade and this is my last homework question help!

Mathematics

1 answer:

Lisa [10]4 years ago

7 0

It’s ok and btw you just need to be confident :)

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What is the value of angle e ?

konstantin123 [22]

Answer:

4 units pls mark me brainliest i really need it thanks

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Find each product. 1. 2x(x^2-6x+3) 2. 2a^2(5b^2 + 3ab + 6a + 1)

hoa [83]

Given:

The expressions are:

$2x(x^2-6x+3)$

$2a^2(5b^2+3ab+6a+1)$

To find:

The product of each expression.

Solution:

According to the distributive property of multiplication over addition, we get

$a(b+c)=ab+ac$

The first expression is:

$2x(x^2-6x+3)$

Using distributive property of multiplication over addition, we get

$2x(x^2-6x+3)=(2x)(x^2)+(2x)(-6x)+(2x)(3)$

$2x(x^2-6x+3)=2x^3-12x^2+6x$

Therefore, the product of $2x(x^2-6x+3)$ is $2x^3-12x^2+6x$ .

The second expression is:

$2a^2(5b^2+3ab+6a+1)$

Using distributive property of multiplication over addition, we get

$2a^2(5b^2+3ab+6a+1)=(2a^2)(5b^2)+(2a^2)(3ab)+(2a^2)(6a)+(2a^2)(1)$

$2a^2(5b^2+3ab+6a+1)=10a^2b^2+6a^3b+12a^3+2a^2$

Therefore, the product of $2a^2(5b^2+3ab+6a+1)$ is $10a^2b^2+6a^3b+12a^3+2a^2$ .

3 0

3 years ago

Y = 3x + 15 3x + 3y = 9

Zina [86]

Answer:

$\Large\boxed{x=-3}$ $\Large\boxed{y=6}$

Step-by-step explanation:

Given the system of equations

$1)~y=3x+15$

$2)~3x+3y=9$

Divide 3 on both sides of the 2) equation

$3x+3y=9$

$3x\div3+3y\div3=9\div3$

$x+y=3$

Current system

$1)~y=3x+15$

$2)~x+y=3$

Substitute 1) equation into the 2) equation

$x+(3x+15)=3$

Combine like terms

$x+3x+15=3$

$4x+15=3$

Subtract 15 on both sides

$4x+15-15=3-15$

$4x=-12$

Divide 4 on both sides

$4x\div4=-12\div4$

$\Large\boxed{x=-3}$

Substitute the x value into one of the equations to find the y value

$y=3x+15$

$y=3(-3)+15$

$y=-9+15$

$\Large\boxed{y=6}$

Hope this helps!! :)

Please let me know if you have any questions

4 0

2 years ago

If a randomly selected customer was satisfied with his/her meal, what is the probability that the customer ordered fish

vodka [1.7K]

Answer:

87.5%

Step-by-step explanation:

Complete question -

75% of the people who eat at Doug's Diner order fish and 90% of the people who order fish also order fries. Given that 80% of all people who eat at Doug's order fries, what is the probability that a randomly chosen customer orders fries without fish?

Solution

Given

People who order fish at the Doug's Diner = 75%

Out of this 75%, 90% also order fries which means that nearly 67.5% ordered fries with the fish.

Given that, 80% of people dining at Doug's Diner order fries

Then percentage or people who ordered only fires and no fish = 80% - 67.5% = 12.5%

The probability of customers who ordered fish = 100 - 12.5% = 87.5%

7 0

4 years ago

Five fourths of a right angle

sleet_krkn [62]

The answer would be 112.5 plz give me thanks and full rating PLZZZZZZ

8 0

3 years ago