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Harlamova29_29 [7]
2 years ago
13

Solve the equation -3x-11=2(4x-8)-6

Mathematics
2 answers:
quester [9]2 years ago
7 0

Answer:

Step-by-step explanation:

PEMDAS

-3x-11=2(4x-8)-6

-3x-11=8x-16-6

-3x-11=8x-22

-11x-11=-22

-11x= -11

x=1

PSYCHO15rus [73]2 years ago
5 0

Answer:

x = 1

Step-by-step explanation:

- 3x - 11 = 2(4x - 8) - 6 ← distribute and simplify left side

- 3x - 11 = 8x - 16 - 6

- 3x - 11 = 8x - 22 ( subtract 8x from both sides )

- 11x - 11 = - 22 ( add 11 to both sides )

- 11x = - 11 ( divide both sides by - 11 )

x = 1

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Colt1911 [192]

Answer:

THE ANSWER IS THIS FOR THE QUESTION UP TOP

8 0
3 years ago
T: 3(t + 3) + 5(3 + 2t) – 76 = 0
Setler [38]

Answer:

\huge\boxed{\sf t = 4}

Step-by-step explanation:

\sf 3(t+3)+5(3+2t)-76 = 0\\\\Expanding \ Parenthesis\\\\3t + 9 + 15 + 10t -76 = 0\\\\13t + 24 -76 = 0\\\\13t - 52 = 0\\\\Add \ 52 \ to \ both \ sides\\\\13t = 52\\\\Dividing\ both\ sides\ by\ 13\\\\t = 52/13\\\\t = 4\\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
6 0
3 years ago
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Please answer right brineliest to wover right
MA_775_DIABLO [31]

Answer:

10

15

-5

-35

-30

0

Step-by-step explanation:

8 0
3 years ago
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Unit 8: Right Triangles &amp; Trigonometry<br> Homework 2: Special Right Triangles
Kamila [148]

Answer:

17. z=39/sin45=78/\sqrt{2}

    y=39/tan60=39/\sqrt{3}

    x=y/sin60=78/\sqrt{3}

19. x=6\sqrt{3}/tan60=6

    y=2x=12

    z=\sqrt{2}y=12\sqrt{2}

Step-by-step explanation:

17.

because:sin45=39/z    

so:     z=39/sin45=78/\sqrt{2}

then: tan60=39/y

so:    y=39/tan60=39/\sqrt{3}

last:  sin60=y/x

so:    x=y/sin60=78/\sqrt{3}

19.

because: tan60=6\sqrt{3}/x

so:            x=6\sqrt{3}/tan60=6

then:        sin30=x/y

so:            y=x*sin30=2x=12

last:          sin45=y/z

so:            z=sin45*y=\sqrt{2}y=12\sqrt{2}

   

4 0
2 years ago
Read 2 more answers
A regular decagon has a radius of 8 cm. what is the approximate area of the decagon? recall that a decagon is a polygon with 10
lianna [129]

The approximate area of the decagon with a side of 8cm comes to be 492.40 cm².

The side of the regular decagon = 8cm

<h3>What is a regular decagon?</h3>

A regular decagon is a polygon with 10 sides that are equal to each other.

The area of a regular decagon with side a is:

A=\frac{5}{2} a^{2} \sqrt{5+2\sqrt{5} }

So, the area A of the regular decagon with a side of 8cm:

A=\frac{5}{2} 8^{2} \sqrt{5+2\sqrt{5} }

A=160\sqrt{5+2\sqrt{5} }

A=492.40 cm²

Therefore, the approximate area of the decagon is 492.40 cm².

To get more about the decagon visit:

brainly.com/question/19899848

7 0
2 years ago
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