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3 years ago

Angle RZT=110 Angle RZS=3s Angle TZS=8s What are angles RZS and TZS?

1 answer:

6 0

Angles RZT, RZS, and TZS form triangle RZT, so they sum to 180. Thus, we have:

110+3s+8s=180

Simplifying, we have:

11s=70

Dividing by 11, we see that:

s=70/11

Therefore, RZS=3s=210/11, and TZS=8s=560/11.

You might be interested in

Solve the inequality −x/2<4

FinnZ [79.3K]

Isolate the x. First, multiply 2 to both sides

-x/2(2) < 4(2)

-x < 4(2)

-x < 8

Isolate the x. Divide - 1 to both sides (because you are dividing a negative number, flip the sign).

-x/ -1 < 8/-1

x > -8 is your answer

hope this helps

5 0

3 years ago

If Breanna drives a constant speed for 3 hours and travels 180 miles, what is her speed a mile per hour

Georgia [21]

Answer:

60 mph

Step-by-step explanation:

You divide 180 by 3 to get 60 mph

3 0

3 years ago

The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)

Lemur [1.5K]

Answer:

Cardiac output: $F=0.055 L\s$

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output: $F=\frac{A}{\int\limits^T_0 {c(t)} \, dt}$ ---1

A = 3 mg

$\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt$

Do, integration by parts

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}$

Substitute the value in 1

Cardiac output: $F=\frac{3}{54.49}$

Cardiac output: $F=0.055 L\s$

Hence Cardiac output: $F=0.055 L\s$

4 0

2 years ago

6. Write the explicit formula for the geometric sequence of the height of the ball on the 10th bounce.First bounce: 54 inchescom

Nat2105 [25]

The height of the ball initially is 54 inches. The common ratio has been provided which is 0.750.

The explicit formular for the geometric sequence is shown as;

$\begin{gathered} ar^{n-1} \\ \text{Where a is the first term in the sequence,} \\ r\text{ is the common ratio betw}een\text{ every successive term} \\ \text{And n is the nth term} \\ \text{The explicit formular for the height of the ball on the 10th bounce is;} \\ ar^{n-1} \\ 54\times(0.750)^{10-1} \\ 54\times(0.750)^9 \\ 54\times0.07508468\ldots \\ 4.0545 \end{gathered}$

The explicit formula is shown as;

54 x (0.750)^9

The rest is simply to solve for the height on the 10th bounce

5 0

1 year ago

PLEASE HELP DUE TODAY !

igor_vitrenko [27]

Answer:

let x be chips and y be sodas

8x + 4y = 5 ---> for the first hint

4x + 8y = 7------> second hint

0.25 cents is how much chips costs

and 0.75 cents is how much sodas costs

5 0

3 years ago

Read 2 more answers