Answer:
a) 0.778
b) 0.9222
c) 0.6826
d) 0.3174
e) 2 drivers
Step-by-step explanation:
Given:
Sample size, n = 5
P = 40% = 0.4
a) Probability that none of the drivers shows evidence of intoxication.



b) Probability that at least one of the drivers shows evidence of intoxication would be:
P(X ≥ 1) = 1 - P(X < 1)
c) The probability that at most two of the drivers show evidence of intoxication.
P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)
d) Probability that more than two of the drivers show evidence of intoxication.
P(x>2) = 1 - P(X ≤ 2)
e) Expected number of intoxicated drivers.
To find this, use:
Sample size multiplied by sample proportion
n * p
= 5 * 0.40
= 2
Expected number of intoxicated drivers would be 2
$12.35 because if u cross multiply 120/100 and 14.82/x u can solve algebraically and get 12.35
Y+2=3(x+6) is your answer.
Answer:
A) it wouldn't fit
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
Let's say that the smallest is called "a"
We can re-write the question like this:
a+(a+1)+(a+2)+(a+3) = 174
4a+6=174
4a=168
a=42