(4,-5) let me know if im wrong if im right plzeee give me brainliestt
Answer:
x^2 - 8xy + 3y^2 - 2
Step-by-step explanation:
(-8xy + 2x^2 + 3y^2) - unknown = x^2 + 2
- unknown = x^2 + 2 + 8xy - 2x^2 - 3y^2
- unknown = -x^2 + 8xy - 3y^2 + 2
Unknown = x^2 - 8xy + 3y^2 - 2
Check:
(-8xy + 2x^2 + 3y^2) - (x^2 - 8xy + 3y^2 - 2)
= -8xy + 2x^2 + 3y^2 - x^2 + 8xy - 3y^2 + 2
= -8xy + 8xy + 2x^2 - x^2 + 3y^2 - 3y^2 + 2
= x^2 + 2
<h3>
Answer: a < 14 (Choice B)</h3>
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Explanation:
Add 4 to both sides
a-4 < 10
a-4+4 < 10+4
a < 14
The reason why we add 4 to both sides is to undo the "minus 4" that's happening to the variable.
4(x+1) is the only one equal to 0