Explanation:
The compound 
is also known as carbon dioxide. It is a gas. It forms when one carbon atom combines with two oxygen atoms.
This can be illustrated as follows.
Consumption of carbon dioxide gas in very low concentrations is not harmful but consumption of its large concentration is very harmful as it can affect the respiratory system.
Answer: 82.0 g/mole
Explanation:
Use the units to see that if we divide 1.64 grams by 0.0200 moles, we'll get a number that is grams/mole, the definition of formula mass.
1.64/0.0200 = 82.0 g/mole (3 sig figs)
We can't tell from this alone what the molecular formula might be, but C6H10 (cyclohexene) comes close (82.1 grams/mole).
The chemical equation is missbalaced.
The right balanced chemical equation is:
<span>2NaHCO3(s) + 129 kJ ---> Na2CO3(s) + H2O(g) + CO2(g)
Then, now you know that 2 moles of NaHCO3 requires 129 kJ heat, and you just need to convert 25.5 grams of NaHCO3 into number of moles to calculare the amount of heat needed.
A) Number of moles in 25.5 g of NaHCO3, n:
n = grams / molar mass
molar mass NaHCO3 = 23 g/mol + 1g/mol + 12g/mol + 3*16g/mol = 84 g/mol
n = 25.5 g / 84 g/mol = 0.304 mol
B) Heat required
Make the proportion with the theoretical ratio:
2mol / 129 kJ = 0.304 mol / x
=> x = 0.304 mol * 129 kJ / 2 mol = 19.608 kJ
Answer: 19.6 kJ
</span>
Answer:
6.68 x 10^-4
Explanation:
131g ÷ 261.337g/mol = 0.5012685 moles
0.5012685 moles ÷ 750.0 liters =
0.5012685÷ 750.0=0.000668358
6.68 x 10^-4
The reason the molecular formula for a disaccharide is not simply double that of a monosaccharide is because when the covalent bond is formed between the carbons of each sugar, an H of one is removed along with an OH from the other. This resulting loss of an H + OH forms H2O (water), therefore the reaction combining the two sugars covalently is called a "dehydration synthesis."
For example, in combining 2 glucose (C6H12O6) molecules, instead of it being 2 × C6H12O6 = C12H24O12, the dehydration synthesis removes 1 H2O to make room for the C-C covalent bond between the two sugars' carbons. Therefore it is 2 H's and 1 O less than that doubling, or: C12H22O11
