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3 years ago

A sample of an ideal gas is cooled from 50.0°C to 25.0°C in a sealed container at constant volume.

Chemistry

1 answer:

ozzi3 years ago

3 0

Answer: Option (E) is the correct answer.

Explanation:

Since, it is given that the container is sealed one. So, no gas molecule is able to escape into the surrounding. Therefore, average molecular mass of the gas will remain the same.

Also, it is given that gas is cooled down from $50^{o}C$ to $25^{o}C$ . This means that there occurs a decrease in kinetic energy of the molecules of gas as kinetic energy is directly proportional to temperature.

Mathematically, $K.E \propto \frac{3}{2}kT$

Hence, sped of molecules will decrease and molecules become closer to each other with decrease in temperature.

Thus, we can conclude that following values for the gas will decrease.

The average distance between the molecules.

The average speed of the molecules

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Sterling silver is 92.5% silver and 7.5% copper. Its density is 10.25 g/cm3. A sterling silver pendant is added to a graduated c

Mariulka [41]

From the information given:

The volume of the graduated cylinder = 50.0 mL
when a sterling silver pendant is added, the volume increases to = 61.3 mL

∴

The volume of the sterling silver pendant is:

= 61.3 mL - 50.0 mL

= 11.3 mL

Since, 1 mL = 1cm³

Then;

11.3 mL = 11.3 cm³

the density of the sterling silver = 10.25 g/cm³

Using the relation for Density; i.e.

$\mathbf{Density = \dfrac{mass}{volume}}$

$\mathbf{10.25 \ g/cm^3= \dfrac{mass}{11.3 \ cm^3}}$

mass = 10.25 g/cm³× 11.3 cm³

mass of the sterling silver = 115.825 grams

Recall that sterling silver has:

92.5% silver and;
7.5% copper

∴

The mass of the copper contained in the sterling silver pendant can be calculated as:

$\mathbf{= \dfrac{115.825 \ g \times 7.5}{100}}$

= 8.687 grams

Therefore, we can conclude that the mass of the copper contained in the sterling silver pendant is 8.687 grams

Learn more about the relation between Density, Mass, and Volume here:

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3 years ago

Which choice lists the correct order of the coefficients of each substance in the following neutralization reaction when the equ

Gnoma [55]

The third one you have listed

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What amount of heat is produced during the combustion of hexane if the temperature of the calorimeter increases by 4.542 k?

Flauer [41]

Answer:

the answer is 85.66

Explanation:

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El arroz produce electricidad

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El arroz si produce electricidad:)

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3 years ago

A space air is at a temperature of 75 oF, and the relative humidity (RH) is 45%. Using calculations, find: (a) the partial press

earnstyle [38]

Answer:

A) Partial Pressure of dry air = 13.32 KPa

Partial Pressure of water vapour = 1.332 KPa

B) Humidity ratio; X = 0.0691

C) V_p = 0.8384 m³/Kg

Explanation:

A) We are given;

Temperature = 75°F

Relative Humidity = 45%

Now,to calculate the partial pressure, we will use the relationship;

Relative Humidity = (Partial Pressure/Vapour Pressure) × 100%

Making partial pressure the subject;

Partial Pressure = Relative Humidity × Vapour Pressure/100%

From the first table attached, at temperature of 75°F, the vapor pressure is 29.6 × 10^(-3) bar = 29.6 KPa

Thus;

Partial Pressure of dry air = (45 × 29.6)/100

Partial Pressure of dry air = 13.32 KPa

From online values, vapour pressure of water vapour at 75°F = 2.96 KPa

Thus;

Partial Pressure of water vapour = (45 × 2.96)/100 = 1.332 KPa

B) humidity ratio of moist air is given as;

X = 0.62198 pw / (pa - pw)

where;

pw = partial pressure of the water vapor in moist air

pa = atmospheric pressure of the moist air

Thus;

X = (0.62198 × 1.332)/(13.32 - 1.332)

X = 0.0691

C) Formula for moist air specific volume is;

V_p = (1 + (xRw/Ra) × RaT/p

Where;

V_p is specific volume

T is temperature = 75°F = 297.039 K

p is barometric pressure which in this case is standard sea level pressure = 101.325 KPa

pw is partial pressure of the water vapor in moist air = 1.332 KPa

Rw is individual gas constant for water = 0.4614 KJ/Kg.K

Ra is individual gas constant for air = 0.2869 KJ/Kg.K

V_p = (1 + (0.0691 * 0.4614/0.2869)) × 0.286.9 * 297.039/101.325

V_p = 0.8384 m³/Kg

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3 years ago