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trapecia [35]
2 years ago
10

0.0200 moles of a compound is found to have a mass of 1.64 g. Find the formula mass of the compound

Chemistry
1 answer:
KatRina [158]2 years ago
3 0

Answer: 82.0 g/mole

Explanation:

Use the units to see that if we divide 1.64 grams by 0.0200 moles, we'll get a number that is grams/mole, the definition of formula mass.

1.64/0.0200 = 82.0 g/mole (3 sig figs)

We can't tell from this alone what the molecular formula might be, but C6H10 (cyclohexene) comes close (82.1 grams/mole).

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1) Carbon-13: 
                      Proton-6     Neutron-7       Electron-6

2)Atomic mass of element X:
   (55*10+56*20+57*70)/100=56.6
4 0
3 years ago
How many sodium ions are in 3.0 moles of nacl
Elena L [17]
1 molecule of NaCl contains 1 sodium ion (Na+), that's why if we have 3.0 moles of.
NaCl, we have 3.0 moles of Na+.
N(ions) = n(mol) · NA.
N(ions) = 3.0 moles · 6.02·1023 = 18.06 ·1023 ions.
4 0
3 years ago
Read 2 more answers
Arrange the elements in order of increasing ionization energy. Use the
UNO [17]

Answer:

Gallium, Phosphorus, Chlorine, Fluorine

Explanation:

Arrange the elements in order of increasing ionization energy. Use the periodic table to identify their positions on the table.

Drag each tile to the correct box.

Tiles

chlorinefluorinegalliumphosphorus

Sequence

5 0
3 years ago
Read 2 more answers
An atom holds 7 electrons. use orbital notation to model the probable location of its electrons.
zheka24 [161]

Answers:

(a) 1s² 2s²2p³; (b) 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d²; (c) 1s² 2s²2p⁶ 3s²3p⁵

Step-by-step explanation:

One way to solve this problem is to add electrons to the orbitals one-by-one until you have added the required amount.

Fill the subshells in the order listed in the diagram below. Remember that an s subshell can hold two electrons, while a p subshell can hold six, and a d subshell can hold  ten.

(a) <em>Seven electrons </em>

1s² 2s²2p³

There are two electrons in the 2s subshell and three in the 2p subshell. The remaining two electrons are in the inner 1s subshell.

(b) <em>22 electrons </em>

1s² 2s²2p⁶ 3s²3p⁶ 4s²3d²

There are two electrons in the 4s subshell and two in the 2p subshell. The remaining 18 electrons are in the inner subshells.

(c) <em>17 electrons</em>

1s² 2s²2p⁶ 3s²3p⁵

There are two electrons in the 3s subshell and five in the 2p subshell. The remaining 10 electrons are in the inner subshells.

7 0
3 years ago
Given that the freezing point depression constant for water is 1.86°c kg/mol, calculate the change in freezing point for a 0.907
melamori03 [73]

Answer : The correct answer for change in freezing point = 1.69 ° C

Freezing point depression :

It is defined as depression in freezing point of solvent when volatile or non volatile solute is added .

SO when any solute is added freezing point of solution is less than freezing point of pure solvent . This depression in freezing point is directly proportional to molal concentration of solute .

It can be expressed as :

ΔTf = Freezing point of pure solvent - freezing point of solution = i* kf * m

Where : ΔTf = change in freezing point (°C)

i = Von't Hoff factor

kf =molal freezing point depression constant of solvent.\frac{^0 C}{m}

m = molality of solute (m or \frac{mol}{Kg} )

Given : kf = 1.86 \frac{^0 C*Kg}{mol}

m = 0.907 \frac{mol}{Kg} )

Von't Hoff factor for non volatile solute is always = 1 .Since the sugar is non volatile solute , so i = 1

Plugging value in expression :

ΔTf = 1* 1.86 \frac{^0 C*Kg}{mol} * 0.907\frac{mol}{Kg} )

ΔTf = 1.69 ° C

Hence change in freezing point = 1.69 °C

5 0
3 years ago
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