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In chemistry, orbital hybridisation (or hybridization) is the concept of mixing atomic orbitals into new hybrid orbitals (with different energies, shapes, etc., than the component atomic orbitals) suitable for the pairing of electrons to form chemical bonds in valence bond theory.
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In this case, we can consider the following chemical reaction for the oxidation of copper which only occurs at high temperatures:

In such a way, for 0.032 grams of copper, the following grams of copper (II) oxide (black product) are yielded:

Therefore, the percent yield is:

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In a redox reaction electrons are lost and gained in equal numbers. The species that is oxidized gives electrons to the species that is reduced. I hope this helps. Let me know if anything is unclear.
It's an exciting and interesting process but those 5 points aren't worth a decent answer. The whole process is called fractioned distillation where different temperatures are reached, transforming the crude oil in gas. After being hit by a cold source it colds becoming different hydrocarbons depending on the temperatures.
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The correct statement should be the below:
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