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garri49 [273]
3 years ago
10

The decimal form of 2.5

Mathematics
1 answer:
sertanlavr [38]3 years ago
6 0
2.5 is in decimal form already.
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A developer bought 78 trees at a total cost of $4050. The shade trees cost $45 each and the evergreens cost $60 each. How many o
ANTONII [103]

Answer:

Step-by-step explanation:

for 5 feet is $60

2 feet is $150.

sorry if this doesn't help!

6 0
2 years ago
Help! Solve for the value of x.
Ludmilka [50]

Answer:

x=6 degrees

Step-by-step explanation:

I know that 31+(10x-1)=90. Then I have to subtract 31 from 90 to get 10x -1.

That's 59. I solve for x in the equation 59=10x-1.

That is the same thing as 60=10x, which is also the same as 6=x.

4 0
2 years ago
Ellie and Jamie like to bake cookies. Ellie baked 24 chocolate chip cookies, and Jamie baked p peanut butter cookies. Together t
kirza4 [7]

Answer:

C) p + 24 = 56

Step-by-step explanation:

The total number of cookies baked = Number of cookies Ellie baked + Number of cookies Jamie baked

Ellie baked 24 chocolate chip cookies.

Jamie baked p peanut butter cookies.

Total of 56 cookies.

Hence:

56 = p + 24

Therefore, the equation that can be solved for p to find the number of cookies Jamie baked is

p + 24 = 56

Option C is the correct option

7 0
2 years ago
Please answer this question now
lidiya [134]

Answer:

C = (2,2)

Step-by-step explanation:

B = (10 ; 2)

M = (6 ; 2)

C = (x ; y )

|___________|___________|

B (10;2)            M (6;2)             C ( x; y)

So:

dBM = dMC

√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 6)^2]

(2-2)^2 - (6-10)^2 = (y-2)^2 + (x - 6)^2

0 + (-4)^2 = (y-2)^2 + (x - 6)^2

16 = (y-2)^2 + (x - 6)^2

16 - (x - 6)^2 = (y-2)^2

Also:

2*dBM = dBC

2*√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 10)^2]

4*[(0)^2 + (-4)^2] = (y-2)^2 + (x - 10)^2

4*(16) = (y-2)^2 + (x - 10)^2

64 = (y-2)^2 + (x - 10)^2

64 = 16 - (x - 6)^2 + (x - 10)^2

48 = (x - 10)^2 - (x - 6)^2

48 = x^2 - 20*x + 100 - x^2 + 12*x - 36

48 = - 20*x + 100 + 12*x - 36

8*x = 16

x = 2

Thus:

16 - (x - 6)^2 = (y-2)^2

16 - (2 - 6)^2 = (y-2)^2

16 - (-4)^2 = (y-2)^2

16 - 16 = (y-2)^2

0 =  (y-2)^2

0 = y - 2

2 = y

⇒ C = (2,2)

4 0
3 years ago
Find an equation that models the path of a satellite if its path is a hyperbola, a = 55,000 km, and c= 81,000 km. Assume the cen
elena-14-01-66 [18.8K]

Answer:

\frac{x^2}{55000^2} - \frac{y^2}{59464^2} =1

Step-by-step explanation:

the transverse axis is horizontal.

so its a horizontal hyperbola

Center is the origin so center is (0,0)

Equation of horizontal hyperbola is

\frac{x^2}{a^2} - \frac{y^2}{b^2} =1

Given a= 55000 and c= 81000

c^2 = a^2 + b^2

81000^2 = 55000^2 + b^2

subtract 55000^2 on both sides

b  = sqrt(81000^2 - 55000^2)= 59464.27

now plug in the values

\frac{x^2}{55000^2} - \frac{y^2}{59464^2} =1

7 0
3 years ago
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