We will have the following:
First, we have that the problem can be seeing as follows:
Now, knowing this and the the properties of the diagonals we will have that [We use the law of cosines}:
First diagonal [AC} is given by:
So, one of the diagonals has an approximate length of 10.7 ft.
Second diagonal [BD] is given by:
So, the second diagonal has a length of approximately 28.1 ft.
<em>**Diagonals**</em>
We are given the arithmetic series 2, 1 3/5, 1 1/5.. In this case, the arithmetic difference is -2/5 by taking the difference of 2 and 1 3/5 and 1 3/5 and 1/5. The general formula of arithmetic sequence is an = a1 + d*(n-1). Substituting, an = 2 -2/5*(n-1). a25 hence is equal to a25 = 2-2/5*(25-1) = -38/5
For this question, we can assume that RS + ST = RT. So now, we just have to plug in the expressions for these lengths, and solve the equation.
(3x+1) + (2x-2) = 64
Because we are only dealing with one operation, the parentheses aren't necessary.
3x + 1 + 2x - 2 = 64
Next, we should combine like terms on the left side of the equation. We know that 3x + 2x = 5x, and that 1 - 2 = -1.
5x - 1 = 64
The goal of an equation is to get the variable alone. To do this, we have to get rid of the -1 on the left side of the equation. So, we are going to add 1 to both sides of the equation, to cancel out the -1 on the left side.
5x = 65
Finally, we are going to divide both sides by 5, as this is the inverse operation of multiplication, which is how the 5 and the x are connected.
x = 13
Therefore, the value of x is 13.
Answer: The proportion that will qualify is 0.0314 or 3.14%.
First, we need to find the z-score of a time of 128 seconds. To do this, we find the difference of the mean and score and divide by the standard deviation.
(128 - 141) / 7 = -1.86
Now, use a standard normal distribution table to determine the percent below a z-score of -1.86. That value is 0.0314 or 3.14%.
In 1st month let she exercised h hours
in second month she exercised h+4 hours
in third month she exercised h+4-3=h+1 hours
Now
- h+h+4+h+1=101
- 3h+5=101
- 3h=96
- h=32hours