We know that
in the first triangle
the ratio of the legs are
4.5/1.5-----> 3
then
case <span>A) 6 m and 2 m ------> ratio=6/3----> 3
so
</span><span>the legs of a second triangle are proportional to the lengths of the legs of the first triangle
</span>case B) 8 m and 5 m ------> ratio=8/5---->1.6
so
the legs of a second triangle are not proportional to the lengths of the legs of the first triangle
case C) 7 m and 3.5 mm ------> ratio=7/3.5---->2
so
the legs of a second triangle are not proportional to the lengths of the legs of the first triangle
case D) 10 m and 2.5 m ------> ratio=10/2.5---->4
so
the legs of a second triangle are not proportional to the lengths of the legs of the first triangle
case E) 11.25 m and 3.75 m ------> ratio=11.25/3.75---->3
so
the legs of a second triangle are proportional to the lengths of the legs of the first triangle
the answer is
A) 6 m and 2 m
E) 11.25 m and 3.75 m
Answer:
7x° + 11x° = 90°
(Required equation)
Step-by-step explanation:
7x° + 11x° = 90°
(complementary angles)
18x° = 90°
18x = 90
x = 90/18
x = 5
Answer:
so the answer is 16? I dont know , need a better explanation on the question. ill answer until then.
Step-by-step explanation:
