If u have 8 points how many triangles can u make with

After picking apples at the orchard, you made these observations: Brad picked twice as many apples as you did, Andy picked 20 fe

frozen [14]

Answer:

Brad picked 130 apples. Andy picked 45 apples. Krystal picked 115 apples.

Step-by-step explanation:

B = 2Y A = Y - 20 K = Y + 50 B + A + K + Y = 355

130 = 2(65) 45 = 65 - 20 115 = 65 + 50 130 + 45 = 115 + 65 = 355

130 = 130 45 = 45 115 = 115

If this answer is correct, please make me Brainliest!

5 0

3 years ago

S=[E,F,G,H,J] identify the ways to select two members from s allowing the repetition

Fofino [41]

Answer: There are 25 ways to select two members.

Step-by-step explanation:

Since we have given that

S={E,F,G,H,J}

Number of elements = 5

We need to select two members from S allowing the repetition.

We will use "Fundamental theorem of counting":

There are 5 choices for the first member.

There are 5 choices for the second member.

So, Number of ways would be

$5\times 5\\\\=25$

Hence, there are 25 ways to select two members.

8 0

3 years ago

Please help me with this algebra PLEEASSEee!!!

amid [387]

11. 5x^2-30=0
+30 to both sides
5x^2=30
÷5 both sides
x^2=6
square root both sides
x= +square root 6 ,- square root 6

12. 4x^2+10=26
-10 both sides
4x^2=16
÷4 both sides
x^2=4
square root both sides
x=+2,-2

13. a=72yrd^2
l=2w
w=?
a=l×w
72=2w×w
72=2w^2
÷2 both sides
36=w^2
square root both sides
w=+6,-6
a measurement can't be - so w=6
Plug into l=2w
l=2×6

l=12
w=6

5 0

3 years ago

Grace wants to find the probability of a family of 3 children having 2 boys and 1 girl. Use a tree diagram to list the possibili

pychu [463]

Answer:

Step-by-step explanation:

My approach was to draw out the probabilities, since we have 3 children, and we are looking for 2 boys and 1 girl, the probabilities can be Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy. So a 2/3 chance if you think about it, your answer 2/3 can't be correct. If we assume that boys and girls are born with equal probability, then the probability to have two girls (and one boy) should be the same as the probability to have two boys and one girl. So you would have two cases with probability 2/3, giving an impossible 4/3 probability for both cases. Also, your list "Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy" seems strange. All of those are 2 boys and 1 girl, so based on that list, you should get a 100 percent chance. But what about Boy-Girl-Girl, or Girl-Girl-Girl? You get 2/3 if you assume that adjacencies in the (ordered) list are important, i.e., "2 boys and a girl" means that the girl was not born between the boys.

5 0

2 years ago

A consulting firm had predicted that 35% of the employees at a large firm would take advantage of a new company Credit Union, bu

m_a_m_a [10]

Answer:

a) 0.4770

b) 3.9945

c) z-statistics seem a large value

Step-by-step explanation:

a. Find the standard deviation of the sample proportion based on the null hypothesis

Based on the null hypothesis:

$p_{0}$ : 0.35

and the standard deviation σ = $\sqrt{p_{0} *(1-p_{0}) }$ = $\sqrt{0.35 *0.65 }$ ≈0.4770

b. Find the z statistic

z-statistic is calculated as follows:

z= $\frac{X-p_{o} }{\frac{s}{\sqrt{N} } }$ where

X is the proportion of employees in the survey who take advantage of the Credit Union ( $\frac{138}{300}=0.46$ )
$p_{0}$ is the proportion in null hypothesis (0.35)
s is the standard deviation (0.4770)
N is the sample size (300)

putting the numbers in the formula:

z= $\frac{0.46-0.35} }{\frac{0.4770}{\sqrt{300} } }$ = 3.9945

c. Does the z statistic seem like a particularly large or small value?

z-statistics seem a large value, which will cause us to reject the null hypothesis.

4 0

3 years ago