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Tems11 [23]
3 years ago
13

A bag has 2 blue marbles, 3 red marbles, and 5 white marbles. Which events have a probability greater than 1/5? Check all that a

pply.
choosing 1 blue marble
choosing 1 red marble
choosing 1 red marble, not replacing it, and then choosing a blue marble
choosing 1 white marble, replacing it, and choosing another white marble
choosing 1 white marble
Mathematics
2 answers:
My name is Ann [436]3 years ago
3 0
The third choice will be correct
DaniilM [7]3 years ago
3 0

Answer:

choosing 1 red marble ; choosing 1 white marble, replacing it, and choosing another white marble ; and choosing 1 white marble

Step-by-step explanation:

There are 2+3+5 = 10 marbles.  The probability of choosing 1 blue marble is 2/10 = 1/5; this is not greater than 1/5.

The probability of choosing 1 red marble is 3/10; this is greater than 2/10, which is the same as 1/5.

The probability of choosing 1 red marble is 3/10; not replacing it and choosing a blue marble would then be a probability of 2/9.  Together this is a probability of 3/10(2/9) = 6/90 = 3/45; this is smaller than 9/45, which is the same as 1/5.

The probability of choosing 1 white marble is 5/10 = 1/2; replacing it and choosing another white marble would be 1/2.  Together this is a probability of 1/2(1/2) = 1/4; this is greater than 4/20, which is the same as 1/5.

The probability of choosing 1 white marble is 5/10 = 1/2.  This is greater than 2/10, which is the same as 1/5.

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A square playground is surrounded by a sidewalk on all sides. the sidewalk is 2n+3 yards long on each side of the park.The sidew
faust18 [17]

Answer:

4(2n+2.5) yards.

8n+10 yards.

Step-by-step explanation:

We have been given that a square playground is surrounded by a sidewalk on all sides. The sidewalk is 2n+3 yards long on each side of the park.

Since side walk is 0.5 yard wide, so each side of playground will be 0.5 less than each side of sidewalk.

\text{Length of each side of playground}=\text{Length of each side of sidewalk - Width of sidewalk}

\text{Length of each side of playground}=2n+3-0.5

\text{Length of each side of playground}=2n+2.5

Since playground is square, so perimeter of playground will be 4 times the length of each side of playground.

\text{Perimeter of playground}=4(2n+2.5)

Upon distributing 4 we will get,

\text{Perimeter of playground}=8n+10

Therefore, perimeter of playground will be 4(2n+2.5) yards or 8n+10 yards.

5 0
4 years ago
use the graph that shows the averge number of the heartbeats for an active adult brown bear and hibernating brown bear
julia-pushkina [17]
<span>Given the graph that shows the average number of the heartbeats for an active adult brown bear and hibernating brown bear

Part a</span>.
What does the point (2, 120) represent on the graph?

From the graph the x axis represent the time in minutes while the y axis represent the number of heartbeats.

Therefore, point (2, 120) means that it takes an active adult brown bear an average of 2 minutes to have 120 heartbeat.


Part b.
What does the ratio of the y-coordinate to the x-coordinate for each pair of points on the graph represent?

From the graph the x axis represent the time in minutes while the y axis represent the number of heartbeats.

Therefore, the ratio of the y-coordinate to the x-coordinate for each pair of points on the graph represents the average number of heatbeats of an active brown dear and a hibernating brown dear per minute.


Part c.
Use the graph to find the bear’s average heart rate when it is active and when it is hibernating.

The bear's average heart rate is given by the ratio of the y-coordinate to the x-coordinate for each pair of points on the graph.

This can be obtained by taking any two points from the graph and taking the slope.

Recall that the slope of a line is given by
m= \frac{y_2-y_1}{x_2-x_1}

For the average hearbeat of an active brown bear, using the points (1.5, 90) and (2, 120), we calculate the average heat rate as follows:
Average heart rate = \frac{120-90}{2-1.5} = \frac{30}{0.5} =60 \ beats \ per \ minute

Also, for the average hearbeat of a hibernating brown bear, using the points (1.5, 18) and (2, 24), we calculate the average heat rate as follows:
Average heart rate = \frac{24-18}{2-1.5} = \frac{6}{0.5} =12 \ beats \ per \ minute
4 0
4 years ago
In ΔIJK, k = 7.6 cm, j = 7.5 cm and ∠J=116°. Find all possible values of ∠K, to the nearest 10th of a degree.
Andre45 [30]

Answer:

No Possible Triangles

Step-by-step explanation:

Deltamath

7 0
3 years ago
a local little leauge has a total of 65 players, of whom 20% are left handed how many left handed players are there
geniusboy [140]

Answer:

13 players

Step-by-step explanation:

65 x 0.2 = 13

8 0
3 years ago
Read 2 more answers
For the following exercises, identify the type of data that would be used to describe a response (quantitative discrete, quantit
nikdorinn [45]

Answer:

14: quantitative continuous

16: quantitative discrete

Step-by-step explanation:

Distance can be any non-negative real number, hence it is continuous.

The number of packages has to be a positive integer, hence is discrete.

3 0
3 years ago
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