well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.
![~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160](https://tex.z-dn.net/?f=~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%20%5C%5C%5C%5C%20A%3DP%281%2Brt%29%5Cqquad%20%5Cbegin%7Bcases%7D%20A%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cdotfill%20%26%20%5C%246000%5C%5C%20r%3Drate%5Cto%204%5C%25%5Cto%20%5Cfrac%7B4%7D%7B100%7D%5Cdotfill%20%260.04%5C%5C%20t%3Dyears%5Cto%20%5Cfrac%7B8%7D%7B12%7D%5Cdotfill%20%26%5Cfrac%7B2%7D%7B3%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D6000%5B1%2B%280.04%29%28%5Cfrac%7B2%7D%7B3%7D%29%5D%5Cimplies%20A%3D6000%5Cleft%28%20%5Cfrac%7B77%7D%7B75%7D%20%5Cright%29%5Cimplies%20A%3D6160)
well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.
what if she had left her money for 1 whole year, then
![~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240](https://tex.z-dn.net/?f=~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%20%5C%5C%5C%5C%20A%3DP%281%2Brt%29%5Cqquad%20%5Cbegin%7Bcases%7D%20A%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cdotfill%20%26%20%5C%246000%5C%5C%20r%3Drate%5Cto%204%5C%25%5Cto%20%5Cfrac%7B4%7D%7B100%7D%5Cdotfill%20%260.04%5C%5C%20t%3Dyears%5Cdotfill%20%261%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D6000%5B1%2B%280.04%29%281%29%5D%5Cimplies%20A%3D6240)
so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?
Y+2=-4x+24
2=-4x-y+24
-22=-4x-y
Answer:
13 in
Step-by-step explanation:
let w be width then length is w + 6
the area (A) of a rectangle is calculated as
A = length × width , then
A = w(w + 6) = 91 , that is
w² + 6w = 91 ( subtract 91 from both sides )
w² + 6w - 91 = 0 ← in standard quadratic form
(w + 13)(w - 7) = 0 ← in factored form
equate each factor to zero and solve for w
w + 13 = 0 ⇒ w = - 13
w - 7 = 0 ⇒ w = 7
however, w > 0 then w = 7
and length = w + 6 = 7 + 6 = 13 in
Answer:
y = 2x + 54
Step-by-step explanation:
slope of equation:
(y2-y1)/(x2-x1)
= (72-58)/(9-2)
= 14/7
= 2
y = 2x + b
58 = 2(2) + b
58 = 4 + b
b = 54
Answer:
the first option
Step-by-step explanation:
really, just look at the table.
is the mean value (10.4) larger than the median (13.4) ?
I hope you can see right away that it is not.
and you can see they are not the same either.
so, all the answer options mentioning mean larger than median or equal to median can be ruled out right away.
so, it is between the first two options.
now think ! how do we draw number lines ? a coordinate axis ?
the smaller numbers left, the larger numbers right. the numbers grow from left to right.
the mean value is simply the sum of all measurements divided by the number of measurements (how many median were done). if that is smaller that the median (so, the Mean is left of the Median), it means that the majority of measurements had a result smaller (to the left) than the Median. so, it is skewed-left.
