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3 years ago

What is a stable and radioactive isotopes

1 answer:

4 0

All elements with atomic numbers greater than 83 areradioisotopes meaning that these elements haveunstable nuclei and are radioactive. Elements with atomic numbers of 83 and less, have isotopes (stablenucleus) and most have at least one radioisotope (unstable nucleus).

A Radioisotope is also an isotope by nature. The difference is that radioisotopes are very unstable and contain high levels of nuclear energy and emit this energy in the form of nuclear radiation. Main difference: Isotopes can be stable or unstable, but Radioisotopes are always unstable.

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You have 50 ml of a complex mixture of weak acids that contains some HF (pKa = 3.18) and some HCN (pKa = 9.21). Which is larger,

bonufazy [111]

Answer:

$\frac{[F^{-}]}{[HF]}$ is larger

Explanation:

$pK_{a}=-logK_{a}$ , where $K_{a}$ is the acid dissociation constant.

For a monoprotic acid e.g. HA, $K_{a}=\frac{[H^{+}][A^{-}]}{[HA]}$ and $\frac{[A^{-}]}{[HA]}=\frac{K_{a}}{[H^{+}]}$

So, clearly, higher the $K_{a}$ value , lower will the the $pK_{a}$

In this mixture, at equilibrium, $[H^{+}]$ will be constant.

$K_{a}$ of HF is grater than $K_{a}$ of HCN

Hence, $(\frac{F^{-}}{[HF]}=\frac{K_{a}(HF)}{[H^{+}]})>(\frac{CN^{-}}{[HCN]}=\frac{K_{a}(HCN)}{[H^{+}]})$

So, $\frac{[F^{-}]}{[HF]}$ is larger

5 0

3 years ago

Depending on the reaction, we could monitor the progress towards equilibrium by observing __________.

Alex Ar [27]

Depending on the reaction, we could monitor the progress towards equilibrium by observing the concentration of the reactant and the product are equal with time.

<h3>What is equilibrium?</h3>

Equilibrium is a stage of reaction in which the rate of forwarding reaction is equal to the rate of backward reaction and equilibrium is stable at the reversible state of mode.

The concentration of reactant and product must also be equal or the same as the time then only it can be an equilibrium reaction.

Therefore equilibrium depends on the reaction, the concentration of the reactant and the product are equal with time.

Learn more about equilibrium, here:

brainly.com/question/13463225

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4 0

1 year ago

1. How many moles of hydrogen are needed to completely react with two moles of nitrogen?

Arlecino [84]

N2 + 3H2 --> 2NH3

Answer: 6 moles of hydrogen are needed to react with two moles of nitrogen.

Explanation:

4 0

2 years ago

A blood sample of 4.01 milliliters is collected from a patient to be analyzed for a platelet count. Human blood should have arou

Harlamova29_29 [7]

Given :

Human blood should have around 1.04 kg/L platelets.

A blood sample of 4.01 milliliters is collected from a patient to be analyzed for a platelet count.

To Find :

The expected mass in grams of platelets in the blood sample.

Solution :

1 L of human blood contains 1.04 kg of platelets.

So, amount of platelets is 1 ml blood is :

$=\dfrac{1.04}{1000}\ kg\\\\= \dfrac{1.04\times 1000}{1000}\ gram\\\\= 1.04 \ gram$

Mass of platelets in 4.01 ml blood is :

$m = 1.04\times 4.01\ gram\\\\m = 4.1704\ gram$

Hence, this is the required solution.

3 0

3 years ago

PLEASE HELP ASAP!

choli [55]

Answer:

$\large \boxed{\text{D. 710 g}}$

Explanation:

1. Calculate the molar mass of Na₂SO₄

$\begin{array}{ccc}\textbf{Atoms} &\textbf{M}_{\textbf{r}} & \textbf{Mass/u}\\\text{2Na} & 23 & 46\\\text{1S} & 32 & 32\\\text{4O}&16 & 64\\&\text{TOTAL =} & \mathbf{142}\\\end{array}$

The molar mass of Na₂SO₄ is 142 g/mol.

2. Calculate the moles of Na₂SO₄

$\text{Moles of Na$_{2}$SO}_{4} = \text{2.5 L solution} \times \dfrac{\text{2.0 mol Na$_{2}$SO}_{4}}{\text{1 L solution}} = \text{5.0 mol Na$_{2}$SO}_{4}$

3. Calculate the mass of Na₂SO₄

$\text{Mass of Na$_{2}$SO}_{4} = \text{5.0 mol Na$_{2}$SO}_{4} \times \dfrac{\text{142 g Na$_{2}$SO}_{4}}{\text{1 mol Na$_{2}$SO}_{4}} = \text{710 g Na$_{2}$SO}_{4}\\\\\text{You need } \large \boxed{\textbf{710 g}} \text{ of Na$_{2}$SO}_{4}$

6 0

2 years ago