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N76 [4]
3 years ago
5

What does the smoke in the tube prove scientifically?/

Chemistry
1 answer:
beks73 [17]3 years ago
4 0

Answer:

smokin tha zaza

Explanation:

trust me

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(01.01 MC)<br> Which of the following could be considered a scientific statement
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hmmmm not sure and don't know

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4 years ago
2. Does the aluminum sample (the can) contain more than, (less than or exactly one mole of aluminum? Support answer with calcula
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than, (less than or exactly one mole

6 0
3 years ago
2 horizontal and parallel lines are intersected by 2 diagonal lines to form a triangle with exterior angles. The top angle of th
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z = 117

x + z = 180

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edg 2020

5 0
3 years ago
A neutral atom of Cl-37 has
Ostrovityanka [42]

Answer:

17 protons, 20 neutrons, and 17 electrons​.

Explanation:

A periodic table can be defined as the standard arrangement of chemical elements by atomic number, electronic configuration and chemical properties in a tabular form.

Generally, a proper representation of the mass number and atomic number of chemical elements is key and very important in chemistry.

Furthermore, as a rule, it should be noted that the mass number (nucleon number) is always larger than the atomic number(number of proton).

The mass number of this neutral atom of Cl-37 is 37 and we know that the atomic number (number of protons) of chlorine is 17. Also, the atomic number of an element is equal to the number of its electrons.

A neutral atom of Cl-37 has 17 protons, 20 neutrons, and 17 electrons.

Hence, a neutral atom of Cl-37 can be identified based on its number of protons because it represent its atomic number, which is what is used to differentiate an atom of an element from the atom of another chemical element.

6 0
3 years ago
A 260.0 −mL buffer solution initially contains 2.5×10−2 M of HCHO2 and 2.5×10−2 M of NaCHO2
FinnZ [79.3K]

The mass of HCHO2 and NaCHO2 to be added to the buffer solution are 0.23g and 0.44g respectively

Data;

  • Volume of solution = 260mL
  • conc. of HCHO2 = 2.5*10^-2M
  • conc. of NaCHO2 = 2.5*10^-2M

<h3>Mass of Reagent Added</h3>

To calculate the mass of reagent added,  let's start with HCHO2

The mass of HCHO2 to be added is the number of moles of HCHO2 multiplied by it's molar mass.

260*10^-^3 * 2.5*10^-^2 * 46 = 0.229 = 0.23g

The mass of NaCHO2 to be added in the buffer solution is

260*10^-^3*2.5*10^-^2*68 = 0.442 = 0.44g

The mass of HCHO2 and NaCHO2 to be added to the buffer solution are 0.23g and 0.44g respectively

Learn more about buffer solution here;

brainly.com/question/22390063

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2 years ago
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