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Ede4ka [16]
3 years ago
15

44. Convert the following. Express your answers in

Chemistry
1 answer:
professor190 [17]3 years ago
4 0

Answer:

A =  0.75 ×10² KJ.

B = 3.9 ×10³ dg

C = 0.22 × 10² μl.

Explanation:

A =  7.5 ×10⁴ j to kilo joules

7.5 ×10⁴ / 1000 = 0.75 ×10² KJ.

Joule is the smaller unit while kilo joule is the larger unit. One kilo joule equals to the thousand joule that's why we will divide the given value by 1000 in order to convert into KJ.

B = 3.9 ×10⁵ mg to decigrams.

3.9 ×10⁵ / 100 = 3.9 ×10³ dg

Decigram is larger unit while milligram is smaller unit. One decigram is equal to the 100 milligram. In order to convert the given value into  decigram we have to divide the value by 100.

C = 2.21 ×10⁻⁴ dL to micorliters

2.21 ×10⁻⁴ ×10⁵ = 0.22 × 10² μl.

Deciliter is bigger unit then micro liter . One deciliter equals to the 100000 micro liters. In order to convert the dL into micro liter we have to multiply the given value with 100000.

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A piece of iron is heated to 120'C then placed in a calorimeter containing 50g of water. The water temperature is raised from 30
Lana71 [14]

Answer:

Mass of iron = 59.375 gm

Explanation:

Calories ( or joules) are added to the water by the hot steel so at the endpoint they are BOTH at 40 C

 The water gains:

     4.18  j/g-C  * 50 * (40-30 C) = 2090 j

The steel gave up 2090 j going from 120 to 40 C

2090 = .44 j/g-C  * m * (120-40)    solve fro m = 59.375 gm

3 0
2 years ago
The half-life of radium-226 is 1590 years. if a sample contains 100 mg, how many mg will remain after 1000 years?
AlladinOne [14]

Answer:

64.52 mg.

Explanation:

The following data were obtained from the question:

Half life (t½) = 1590 years

Initial amount (N₀) = 100 mg

Time (t) = 1000 years.

Final amount (N) =.?

Next, we shall determine the rate constant (K).

This is illustrated below:

Half life (t½) = 1590 years

Rate/decay constant (K) =?

K = 0.693 / t½

K = 0.693/1590

K = 4.36×10¯⁴ / year.

Finally, we shall determine the amount that will remain after 1000 years as follow:

Half life (t½) = 1590 years

Initial amount (N₀) = 100 mg

Time (t) = 1000 years.

Rate constant = 4.36×10¯⁴ / year.

Final amount (N) =.?

Log (N₀/N) = kt/2.3

Log (100/N) = 4.36×10¯⁴ × 1000/2.3

Log (100/N) = 0.436/2.3

Log (100/N) = 0.1896

Take the antilog

100/N = antilog (0.1896)

100/N = 1.55

Cross multiply

N x 1.55 = 100

Divide both side by 1.55

N = 100/1.55

N = 64.52 mg

Therefore, the amount that remained after 1000 years is 64.52 mg

7 0
3 years ago
How is the frequency of an EM wave related to its energy
natulia [17]

Answer:

Higher the frequency, the higher the energy

Explanation:

Please help me by marking me brainliest. I'm really close :)

6 0
3 years ago
Read 2 more answers
Calculate the mass in grams of benzophenone required to make a solution of 2.5 mmoles
kirill115 [55]

Answer:

0.46 grams (C₆H₅)₂CO

Explanation:

To find the mass of benzophenone ((C₆H₅)₂CO), you need to (1) convert mmoles to moles and then (2) convert moles to grams (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units. The final answer should have 2 sig figs to match the sig figs of the given value (2.5 mmoles).

Molar Mass ((C₆H₅)₂CO): 13(12.011 g/mol) + 10(1.008 g/mol) + 15.998 g/mol

Molar Mass ((C₆H₅)₂CO): 182.221 g/mol

2.5 mmoles (C₆H₅)₂CO               1 mole                  182.221 g
-----------------------------------  x  ------------------------  x  -------------------  =
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=  0.46 grams (C₆H₅)₂CO

4 0
1 year ago
Which has more particles, a mole of copper (Cu) atoms or a mole of neon
goldfiish [28.3K]

Answer:

D

Explanation:

it is neon because neon has a higher atomic number so it would have more protons and neutrons and electrons in one atom thus having more particles in one mole

7 0
3 years ago
Read 2 more answers
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