30.6 g of AgNO₃
Explanation:
We have the following chemical reaction:
Na₃PO₄ + 3 AgNO₃ → Ag₃PO₄ + 3 NaNO₃
Now we calculate the number of moles of Na₃PO₄:
number of moles = mass / molecular weight
number of moles of Na₃PO₄ = 9.44 / 164 = 0.06 moles
Now we formulate the following reasoning:
if 1 mole of Na₃PO₄ will react with 3 moles of AgNO₃
then 0.06 moles of Na₃PO₄ will react with X moles of AgNO₃
X = (0.06 × 3) / 1 = 0.18 moles of AgNO₃
mass = number of moles × molecular weight
mass of AgNO₃ = 0.18 × 170 = 30.6 g
Learn more about:
mole concept
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Answer:
x = 1 x 10⁻²
Explanation:
Since the pH is the same in both cases, the two expressions for pH can be set equal to each other:
pH = 4 + log(x) = -log[H⁺]
The hydrogen ion concentration ([H⁺]) is 0.01 M, so this value can be substituted in the equation:
4 + log(x) = -log(0.01)
4 + log(x) = 2
log(x) = -2
x = 10⁻²
A moon jellyfish has a transparent body.
The balanced equation for the above reaction is as follows;
2HCl + K₂SO₃ ---> 2KCl + H₂O + SO₂
stoichiometry of HCl to SO₂ is 2:1
number of moles of HCl reacted - 15.0 g / 36.5 g/mol = 0.411 mol
according to molar ratio
number of SO₂ moles formed - 0.411 mol /2 = 0.206 mol
since we know the number of moles we can find volume using ideal gas law equation
PV = nRT
where
P - pressure - 1.35 atm x 101 325 Pa/atm = 136 789 Pa
V - volume
n - number of moles - 0.206 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 325 K
substituting values in the equation
136 789 Pa x V = 0.206 mol x 8.314 Jmol⁻¹K⁻¹ x 325 K
V = 4.07 L
volume of SO₂ formed is 4.07 L
1.55 x 10^9
Just slide the decimal over to the left 9 times and this is what you will get.
