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Olin [163]
3 years ago
9

Mark deposited $9,000 into two saving accounts bearing simple interest. One of the accounts has an interest rate of 8% while the

other rate is 7%. If the total interest earned after one year is $700, find the amount deposited into each of the accounts
Mathematics
1 answer:
geniusboy [140]3 years ago
8 0
0.07x+0.08 (9000-x)=700
Solve for x
0.07x+720-0.08x=700
0.07x-0.08x=700-720
-0.01x=-20
X=20÷0.01
X=2,000 invested at 7%

9000-2000=7000 invested at 8%
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Answer:

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Step-by-step explanation:

Please consider the complete question.

Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds after she jumps for the bone can be representedh(t)=-16t^2+20t.

What is Spot's average rate of ascent, in feet per second, from the time she jumps into the air to the time she catches the bone at t=1/2?  

We will use average rate of change formula to solve our given problem.

\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}

\text{Average rate of change}=\frac{h(\frac{1}{2})-h(0)}{\frac{1}{2}-0}

\text{Average rate of change}=\frac{-16\cdot(\frac{1}{2})^2+20\cdot \frac{1}{2}-(-16\cdot(0)^2+20\cdot (0))}{\frac{1}{2}-0}

\text{Average rate of change}=\frac{-16\cdot\frac{1}{4}+10-(0)}{\frac{1}{2}}

\text{Average rate of change}=\frac{-4+10}{\frac{1}{2}}

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\text{Average rate of change}=\frac{2\cdot 6}{1}

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