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3 years ago

The graph shows two polygons ABCD and A′B′C′D′.

Mathematics

2 answers:

stellarik [79]3 years ago

7 0

Answer:

Translate ABCD down 1, then reflect it over the y-axis

and

Reflect ABCD over the y-axis, then translate down 1

Step-by-step explanation:

First of all, the two steps are the same, just in a different order

Second, if you look at the instructions you can see what would happen to the quadrilateral. Reflecting over the y-axis would make the shape flip horizontally (left to right), as shown in the image. This means the points on the left move to the right, and the points on the right move to the left. Top and bottom points stay the same. And the "translation" just means to slide. In both the answers, it says "translate 1 unit down", which just means "move 1 unit down", which is exactly what happens in the image

MatroZZZ [7]3 years ago

3 0

Translate ABCD down 1, then reflect it over the y-axis and Reflect ABCD over the y-axis, then translate down 1

Hope this helps!

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igor_vitrenko [27]

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3 years ago

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r-ruslan [8.4K]

Answer:

y = 1, 1.319, 1.024, 0

Step-by-step explanation:

Given equation:

$y=(1+x)\cos x$

$\textsf{when}\:x=0:$

$\begin{aligned} \implies y & =(1+0)\cos 0\\\implies y & = 1\end{aligned}$

$\textsf{when}\:x=\dfrac{\pi}{6}:$

$\begin{aligned} \implies y & =\left(1+\frac{\pi}{6}\right)\cos \left(\frac{\pi}{6}\right)\\\implies y & = 1.319\: \sf (3\:dp)\end{aligned}$

$\textsf{when}\:x=\dfrac{\pi}{3}:$

$\begin{aligned} \implies y & =\left(1+\frac{\pi}{3}\right)\cos \left(\frac{\pi}{3}\right)\\\implies y & = 1.024\: \sf (3\:dp)\end{aligned}$

$\textsf{when}\:x=\dfrac{\pi}{2}:$

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8 0

2 years ago

The amount of money Chaz earned for walking dogs is given in the table. Can the relationship be described by a constant rate? Ex

mojhsa [17]

Answer:

Yes, the relationship can be described by a constant rate of $18.75 per dog

Step-by-step explanation:

see the attached figure to better understand the problem

Let

x ----> the number of dogs

y ---> the amount of money earned

we have the points

$(6,112,50), (8,150), (11,206.25)$

step 1

Find the slope with the first and second point

$(6,112,50), (8,150)$

$m=(150-112.50)/(8-6)=18.75$

step 2

Find the slope with the first and third point

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$m=(206.25-112.50)/(11-6)=18.75$

Compare the slopes

The slopes are the same

That means, that the three points lies on the same line

therefore

Yes, the relationship can be described by a constant rate of $18.75 per dog

7 0

2 years ago

Help urgent, which functions are bounded below but not above? Choose all answers that apply.

evablogger [386]

Answer:

c, e, f, and i

Step-by-step explanation:

a. is bounded above at y = 1 and below at y = 0

b. is unbounded both above and below

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d. is unbounded both above and below

e. is bounded below at y = 0 and unbounded above

f. is bounded below at y = 0 and unbounded above

g. is bounded below at y = 0 and bounded above at y = 1

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i. is bounded below at y = 0 and unbounded above

j. is unbounded both above and below

3 0

3 years ago

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SVETLANKA909090 [29]

Answer:

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Explanation:

Given f(n) and g(n) defined below:

$\begin{gathered} f\mleft(n\mright)=n^2-3 \\ g\mleft(n\mright)=4n-1 \end{gathered}$

First, we evaluate g(1):

$\begin{gathered} g\mleft(1\mright)=4(1)-1 \\ =4-1 \\ g(1)=3 \end{gathered}$

Therefore:

$\begin{gathered} f\mleft(g(1)\mright)=f\mleft(3\mright) \\ f\mleft(3\mright)=3^2-3 \\ =9-3 \\ =6 \end{gathered}$

Therefore, f[g(1)]=6.

8 0

1 year ago