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3 years ago

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Nao and Arban drive to work. Nao drives 95 miles in 2.5 hours. Arban drives 128 km in 1 hour 15 min. Work out the difference bet

ween their average speeds in km/h. 1 mile = 1.6 km

1 answer:

statuscvo [17]3 years ago

4 0

Answer:

Nao = 95/2.5 = 38 miles per hour

15 min x (1 hour / 60 min) = .25

Arban = 128 km x (1 mile / 1.6 km) / 1.25 hour = 64 miles per hour

Step-by-step explanation:

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the prime factorization of a number is 2 to the power of 3 x 3 to the power of 2 x5 wich statement is true about these factors?

Naddik [55]

Answer:

Fifteen is a factor of the number because both 3 and 5 are prime factors.

Step-by-step explanation:

2^3 * 3^2 * 5

= 2 * 2 * 2 * 3 * 3 * 5

As you can see from, the prime factors are 2, 3, and 5.

3 × 5 = 15, option A is correct.

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2 years ago

Read 2 more answers

PLEASE HELP ME! :(

snow_lady [41]

Here, I'll do the first one for you.
When they are talking about a number, use "x".
Since it says twice a number, you say 2x. Or 3x for three times the number
2x+12=3x-31
Then use algebra to find x. Get the numbers on one side and all the x's on the other.
2x+12+31=3x-31+31
2x+43-2x=3x-2x
x=43

Now do the rest on your own!

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2 years ago

The function h(t) = –16t2 + 96t + 6 represents an object projected into the air from a cannon. The maximum height reached by the

jolli1 [7]

If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.

The derivative is      h'(t) = -32 t + 96 .

At the maximum ... h'(t) = 0

   32 t = 96 sec

   t =  3 sec .
___________________________________________

If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.

In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.

   150 ft = -16 t² + 96 t + 6

Subtract 150ft from each side: -16t² + 96t - 144 = 0 .

Before you attack that, you can divide each side by -16,
making it a lot easier to handle:

     t² - 6t + 9 = 0

I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)

The answer is from AL2006

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3 years ago

What is 98,464 rounded to the nearest ten thousands ?

sleet_krkn [62]

100,000
because the 8 makes the 9 round up into a 10

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3 years ago

Name the line of reflection used to map each preimage to its image

rewona [7]

Answer:

From the picture attached,

9). When pre-image KLMN is a reflected across x = -2, we get image K'L'M'N'.

Therefore, line of reflection will be x = -2

10). In this picture line of reflection which passes through origin (0, 0) and slope = 1 will be,

y = x.

11). Since, all the points of image and preimage points are equidistant from x-axis, line of reflection will be x-axis or y = 0.

12). Line passing through midpoint of the line joining BB' will be the line of reflection.

Coordinates of B → (5, 3)

Coordinates of B' → (5, 7)

Coordinates of BB' → → (5, 5)

Therefore, line of reflection will be y = 5.

13). Coordinates of G → (2, 5)

Coordinates of G' → (-2, 5)

Midpoint joining the segment GG' → → (0, 5)

Therefore, line of reflection → x = 0

14). Line of reflection passing through (0, 0) and slope = -1

y = -x

Step-by-step explanation:

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2 years ago