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AfilCa [17]
3 years ago
8

Mr lim had 3kg of sugar . He divided the sugar into 5 equal amounts.what is the mass of eacy amount of sugar give your answer as

a fraction

Mathematics
1 answer:
kicyunya [14]3 years ago
6 0
Divide total # kg by the # of parts it is divided in to.

=3 kg ÷ 5 parts
=3/5 kg

Hope this helps! :)
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Martin uses his power saw every 15 seconds.How many times did he use it in one hour ?​
Alina [70]

Answer:

  1. 60<em><u>÷</u></em><em><u>15</u></em><em><u> </u></em><em><u>=</u></em><em><u>4</u></em><em><u> </u></em>

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7 0
3 years ago
Read 2 more answers
Pls help me I reallyyyyy don't understand
mash [69]

Answer:

9

Step-by-step explanation:

range is the range from the lowest # through the biggest # in other words subtract the smaller number from the bigger number

8 0
3 years ago
Help me please I only have 5 mins left
Ivahew [28]

Answer:

A.5

B.16

C.11

D.3

E.5

Step-by-step explanation:

6 0
3 years ago
L.F. Richardson proposed a model to describe the spread of war fever. His proposal: If y(t) is the percent of the population adv
Lena [83]

Answer:

y'(t)=ky(t)(100-y(t))

Step-by-step explanation:

The rate of change of y(t) at any time is the derivative of y with respect to time y, y'(t)

If y(t) is the percent of the population advocating war at time t

then 100-y(t)  is the percent of the population not advocating war

The product of the percentage of the population advocating war and the percentage not advocating war would be

y(t)(100-y(t))

If the rate of change of y(t) at any time is proportional to the product of the percentage of the population advocating war and the percentage not advocating war, then

y'(t)=ky(t)(100-y(t))

where <em>k is the constant of proportionality </em>

8 0
3 years ago
An instructor wants to write a test with 25 questions where each question is worth 3, 4, or 5 points based on difficulty. He wan
irakobra [83]

ANSWER

Find out the how many 3, 4, and 5 point questions could there be.

To proof

Let us assume that the 3 points based question be = x

Let us assume that the 4 points based question be = y

Let us assume that the 5 points based question be = z

As given

An instructor wants to write a test with 25 questions

than the equation become in the form

x + y + z = 25

he quiz to be worth a total of 100 points.

than the equation is becomes

3x + 4y + 5z =100

As given

He wants the number of 3-point questions to be 4 less than the number of 4-point questions

x = y -4

Than the three equation are

x + y + z = 25 ,3x + 4y + 5z =100 and x = y -4

put  x = y -4 in the x + y + z = 25 ,3x + 4y + 5z =100

than

2y + z = 29, 7y +5z= 112

multiply 2y + z = 29 by 5 and subtracted 7y +5z= 112

10 y -7y + 5y -5y = 145 -112

3y = 33

y = \frac{33}{3}

y =11

put in the  x = y -4

x = 11-4

x= 7

put the value of x ,y in the x + y + z = 25

7 + 11 +z =25

18 +z = 25

z = 25 -18

z=7

therefore

numbers of the 3 point question be = 7

numbers of the 4 point question be = 11

numbers of the 5 point question be = 7

Hence proved



3 0
3 years ago
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