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Aneli [31]
3 years ago
5

3. The following data was recorded from the heights of planted flowers in inches: 12, 10, 8.5, 5.5, 10. Calculate the Mean Absol

ute Deviation (MAD) for the heights of the flowers.
A. 10

B. 9.2

C. 1.76

D. 8.8​
Mathematics
1 answer:
nirvana33 [79]3 years ago
3 0

Answer:

1.76

Step-by-step explanation:

i used a mean absolute deviation calculator

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Which expression is equal to (7 times 2)times 2
Lady bird [3.3K]
The answer is 28. 7x2=14 and then 14x2=28. Remember PEMDAS
7 0
3 years ago
Which of these numbers are rational? (Choose all that apply)
dezoksy [38]

Answer:

-7

Step-by-step explanation:

3 0
3 years ago
If Point P is between Q and R and QP = 16 and Qr = 52. What is the length of PR?
Dimas [21]
1) Here, QR = QP + PR

52 = 16 + PR

PR = 52 - 16 = 36

In short, Your Answer would be Option C

2) Slope of mentioned line:
m = (5+5) / (0-4)
m = 10/-4
m = -5/2

Parallel lines have same slope so it would be -5/2 as well

In short, Your Answer would be Option B

Hope this helps!
5 0
3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the
sladkih [1.3K]

Answer:

10.17 seconds

Step-by-step explanation:

substitute y=0 into the equation

0=-16x²+153x+98

then use the quadratic formula

a = -16

b= 153

c = 98

Substituting values into the Quadratic equation, you get (Round the values to the nearest hundreth):

x₁= 10.17

x₂= -0.60

5 0
3 years ago
Sherman has two sequences . The first sequence is described by the explicit rule f(n) = 15n + 4 and the second sequence is descr
Viktor [21]

Answer:

Step-by-step explanation:

Given the explicit function as

f(n) = 15n+4

The first term of the sequence is at when n= 1

f(1) = 15(1)+4

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 15(2)+4

f(2) = 34

d = 34-19

d = 15

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)15)

S20 = 10(38+19(15))

S20 = 10(38+285)

S20 = 10(323)

S20 = 3230.

Sum of the 20th term is 3230

For the explicit function

f(n) = 4n+15

f(1) = 4(1)+15

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 4(2)+15

f(2) = 23

d = 23-19

d = 4

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)4)

S20 = 10(38+19(4))

S20 = 10(38+76)

S20 = 10(114)

S20 = 1140

Sum of the 20th terms is 1140

7 0
3 years ago
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