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KengaRu [80]
3 years ago
15

Find the area.ParallelogramA = 1/2 bh

Mathematics
2 answers:
JulijaS [17]3 years ago
6 0
The area of parallelogram is not 1/2 bh, but only b×h

A = 16*18 = 288 ft^2

Anyway if the packet says 1/2bh [or (b*h)/2]....(16*18)/2 = 288/2 = 144 ft^2
ratelena [41]3 years ago
5 0
A = b * h
A =  16 * 18
A = 288 ft^2
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What is the function rule​
muminat

Answer:

A function rule describes how to convert an input value (x) into an output value (y) for a given function. An example of a function rule is f(x) = x^2 + 3.

Step-by-step explanation:

3 0
3 years ago
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Solve for x.<br><br> 2/3(x−7)=−2
zaharov [31]
2/3x - 14/3 = -2
3(2/3x - 14/3) = -2(3)
           2x - 14 = -6
                   2x = -6 + 14
                   2x = 8
                     x = 8/2
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hope this helps :)



5 0
4 years ago
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Need help with two questions please
balandron [24]

Answer:

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Step-by-step explanation:

the cubic power doesnt affect the sign

3 0
3 years ago
Please help I really need it for a grade boost.
ArbitrLikvidat [17]

Answer:

I hope This will Help u.. Plz mark me as Brilliant please

Step-by-step explanation:

Before you get started, take this readiness quiz.

Simplify: 

If you missed this problem, review (Figure).

Solve Equations with Constants on Both Sides

In all the equations we have solved so far, all the variable terms were on only one side of the equation with the constants on the other side. This does not happen all the time—so now we will learn to solve equations in which the variable terms, or constant terms, or both are on both sides of the equation.

Our strategy will involve choosing one side of the equation to be the “variable side”, and the other side of the equation to be the “constant side.” Then, we will use the Subtraction and Addition Properties of Equality to get all the variable terms together on one side of the equation and the constant terms together on the other side.

By doing this, we will transform the equation that began with variables and constants on both sides into the form  We already know how to solve equations of this form by using the Division or Multiplication Properties of Equality.

Solve: 

Solution

In this equation, the variable is found only on the left side. It makes sense to call the left side the “variable” side. Therefore, the right side will be the “constant” side. We will write the labels above the equation to help us remember what goes where.



Since the left side is the “”, or variable side, the 8 is out of place. We must “undo” adding 8 by subtracting 8, and to keep the equality we must subtract 8 from both sides.

Use the Subtraction Property of Equality.Simplify.Now all the variables are on the left and the constant on the right.

The equation looks like those you learned to solve earlier.Use the Division Property of Equality.Simplify.Check:Let .

Solve: 



Solve: 



Solve: 

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4 0
3 years ago
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How many ways can 6 people be chosen and arranged in straight line if there are 8 people to choose from? a. 48.b. 720.c. 20, 160
Ipatiy [6.2K]

Answer:

<h2>C. <em>20,160</em></h2>

Step-by-step explanation:

This question bothers on permutation since we are to select a some people out of a group of people and then arrange in a straight line. If r object are to be arranged in a straight line when selecting them from n pool of objects. This can be done in nPr number of ways.

nPr = n!/(n-r)!

Selection of 6 people out of 8 people can therefore be done in 8C6 number of ways.

8P6 = 8!/(8-6)!

8P6 = 8!/2!

8P6 = 8*7*6*5*4*3*2!/2!

8P6 = 8*7*6*5*4*3

8P6 = 56*360

8P6 = 20,160

<em>Hence this can be done in 20,160 number of ways</em>

5 0
3 years ago
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