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lianna [129]
2 years ago
5

Pwease help i will give you brain thing if its correct ♡

Mathematics
1 answer:
Oliga [24]2 years ago
6 0

Answer:

1. A, B, C, E

2.Im not sure I think A

hope this helps

have a good day :)

Step-by-step explanation:

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Subtract. Write the difference in simplest form. (6p + 3) - (2p + 1)
Sonja [21]

Answer:

4p + 2

Step-by-step explanation:

(6p + 3) - (2p + 1)

Distribute the minus sign

6p +3 -2p -1

4p +2

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3 years ago
What is the point 2,1 dilated by the scale factor of 2.5
Inga [223]
The answer would be -0.4
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A city planner designs a park that is a quadrilateral with vertices at J(-3,1), K(1,3), L(5,-1), and M(-1,-3). There is an entra
Ksivusya [100]
The Quadrilateral is JKLM, 

let M_{JK}, M_{KL}, M_{LM}, M_{JM}, be the midpoints of JK, KL, LM and JM respectively.

---------------------------------------------------------------------------------------------------------

Given any 2 point P(m,n) and Q(k,l),<span>

the coordinates of the midpoint of the line segment PQ are given by the formula:

M_{PQ}=( \frac{m+k}{2} ,&#10;\frac{n+l}{2}), </span>

-------------------------------------------------------------------------------------------------

thus the coordinates of points M_{JK}, M_{KL}, M_{LM}, M_{JM},

are as follows:

M_{JK}= (\frac{-3+1}{2}, \frac{1+3}{2})=(-1,2), \\\\M_{KL}= (\frac{1+5}{2}, \frac{3-1}{2}=(3,1), \\\\M_{LM}= (\frac{5-1}{2}, \frac{-1-3}{2})=(2, -2),\\\\ M_{JM}= (\frac{-3-1}{2}, \frac{1-3}{2})=(-2,-1)


------------------------------------------------------------------------------------------------

The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:<span>

 |PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}&#10;}</span>

------------------------------------------------------------------------------------------------

thus the distances connecting the opposite entrances can be calculated as follows:


|M_{JK},M_{LM}|= \sqrt{ (-1-2)^{2} + (2-(-2))^{2} }= \sqrt{9+16}=5

|M_{KL}M_{JM}|= \sqrt{ (3-(-2))^{2} + (1-(-1))^{2}}= \sqrt{25+4}= \sqrt{29}=5.39


Thus the total distance of the paths joining the opposite entrances is 

5+5.39 units = 50 m + 53.9 m = 104 m (rounded to the nearest meter)


Answer: 104 m



8 0
3 years ago
Cassie has test grades of 71, 78 and 83 on the first three tests in her
Neporo4naja [7]

Answer:

x ≥ 88

Step-by-step explanation:

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