If you didn't change the slope of the line, but you moved it
down 6 units on the graph, then its y-intercept would become
6 less. The equation of the new line would be ...
y = 1/3 x - 16 .
Step-by-step explanation:
The first expression is :
Numerator = -11×2 = -22
Denominator = 3
So, answer will be :
(negative)
The second expression is:
Numerator = -11×-2 = 22
Denominator = 3
So, the answer will be :
(positive)
Hence, this is the required solution.
Answer:
<u>Step-by-step explanation:</u>
Note the following identities: tan² x = sec²x - 1
tan² x + sec x = 1
(sec² x -1) + sec x = 1
sec² x + sec x - 2 = 0
(sec x + 2)(sec x - 1) = 0
sec x + 2 = 0 sec x - 1 = 0
sec x = -2 sec x = 1
Answer:
y + 5 = (3/2)(x - 4)
Step-by-step explanation:
The point-slope formula is y - k = m(x - h). We get h and k from the given point: h = 4 and k = -5, and m from the given slope: 3/2. Then we have:
y + 5 = (3/2)(x - 4)
148.57-94 would equal 54.57