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spayn [35]
3 years ago
10

Identify each function as a constant, direct variation, absolute value, or greatest integer function.

Mathematics
1 answer:
Anton [14]3 years ago
7 0
None of those describe this function.

It's not a constant function, because it is not equal to a constant (something that isn't a variable)

It doesn't show direct variation, because it can't be represented in the form
y = kx.

It isn't an absolute value function because the absolute value isn't taken anywhere.
If it was an absolute value function it would look something like this:
g(x) = |x+3|

It isn't a greatest integer function, because the greatest integer isn't taken anywhere.
If it was a greatest integer function it would look something like this:
g(x) = \left \lfloor{x + 3}\right \rfloor

Are you sure you typed that question right?
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What are the values of x, y, and z ?
aleksklad [387]

Answer:

112

Step-by-step explanation:

8 0
3 years ago
What is the unit rate of 5 pounds of oranges cost 10.45?<br> find the unit rate
nataly862011 [7]

Answer:

The answer is 2.09 per pound.

Step-by-step explanation:

To find the unit rte, you divide 10.45 by 5.

8 0
3 years ago
The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
3 years ago
Which statement best describes the relationship between the positions of the two players
Lena [83]

Answer:

N is M reflected across the x-axis; only the signs of the x-coordinates of M and N are different.

Step-by-step explanation:

The y-axis is vertical, and the x-axis is horizontal. If a point, or image, is reflected over the x-axis, in this case M and N, then the signs of the y-coordinates do not change, and instead the coordinates of the x-axis change.

7 0
3 years ago
So in the thing p=m/v to find m would you times v by p?
EastWind [94]

M = mass

p = density

v = volume

Yes, to find m it would be m = pv.

To find v that would be m/p.

8 0
3 years ago
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