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OverLord2011 [107]
2 years ago
6

What is an equation of the line that passes through the points (0, -4) and (-4, 6)?

Mathematics
1 answer:
olganol [36]2 years ago
8 0

Answer:

The equation of the line is.

y=-\frac{5}{2}x-4

Step-by-step explanation:

Given:

The given points are (0, -4) and (-4, 6)

The equation of the line passing through the points (x_{1},y_{1}) and (x_{2},y_{2}) is.

\frac{x-x_{1}}{x_{2}-x_{1}}=\frac{y-y_{1}}{y_{2}-y_{1}}

Thus, the equation of the line that passes through the points (0, -4) and (-4, 6) is

\frac{x-0}{(-4)-0}=\frac{y-(-4)}{6-(-4)}

\frac{x}{-4}=\frac{y+4}{6+4}

-\frac{x}{4}=\frac{y+4}{10}

-\frac{10x}{4}=y+4

-10x=4(y+4)

-10x=4y+16

4y=-10x-16

The above equation is divided by 2 both sides.

2y=-5x-8

y=-\frac{5}{2}x-4

Therefore, the equation of the line that passes through the points (0, -4) and (-4, 6) is y=-\frac{5}{2}x-4

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