Molar mass of H₂ = 1.008 × 2 g/mol = 2.016 g/mol <span>
Molar mass of I₂ =
126.9 × 2 g/mol = 253.8 g/mol </span><span>
Molar mass of HI = (1.008 + 126.9) g/mol = 127.9 g/mol
H₂(g) + I₂(g) → 2HI </span><span>
Mole ratio H₂ : I₂ : HI = 1 : 1 : 2 </span><span>
Then the initial number of moles of H₂ = (3.35 g) / (2.016 g/mol) = 1.662 mol </span><span>
Initial number of moles of I₂ = (50.75 g) / (253.8 g/mol) = 0.2000 mol <
1.662 mol </span><span>
Hence, I₂ is the
limiting reactant (limiting reagent). </span><span>
Number of moles of I₂ reacted = 0.2000 mol </span><span>
Number of moles of HI reacted = (0.2000 mol) × 2 = 0.4000 mol
<span>Mass of HI reacted = (127.9 g/mol) × (0.4000 mol) = 51.16 g</span></span>
Answer:
The current on the water layer = 1.64×10^-3A
Explanation:
Let's assume that the radius given for the string originates from the centre of the string. The equation for determining the current in the water layer is given by:
I = V × pi[(Rwater + Rstring)^2 - (Rstring)^2/ ( Resitivity × L)
I =[ 166×10^6 ×3.142[(0.519×10^-4) + (2.15×10^-3])^2 - ( 2.15×10^-3)^2] / ( 183 × 831)
I =[ 521572000(4.848×10^6)- 4.623×10^-6]/ 154566
I = 252.83 -(4.623×10^-6)/ 154566
I = 252.83/154566
I = 1.64× 10^-3A
This question is a bit ambiguous because all parts of a scientific argument must be supported by valid data. However, among the choices, the closest synonym to "valid data" would be evidence. Evidence is the body of facts or information that support a given idea.
The period of the musical note is 
seconds.
Answer: Option A
<u>Explanation:</u>
The frequency is defined as the number of oscillations or a complete cycle of wave occurred in a given time interval. So the frequency is inversely proportional to the time period. Thus the mathematical representation of frequency with time period is
As the frequency is given as 
, the time period can be found as
Thus,
Thus the time period for the frequency of the musical note is seconds.
