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Which property allows objects that do not produce their own light

KatRina [158]

Answer:

Reflection

Explanation:

As light is scattered on items which do not generate illumination, they reflect it. This is attributed to the fact that light reflects off of themselves. The moon, for example, absorbs sunlight such that it can be seen at night.

8 0

3 years ago

Help with this question please.

sergij07 [2.7K]

Answer: Yes Because it matches with the mass and the amount of force Hope this helps :>

Explanation:

3 0

2 years ago

The product of voltage across a device and the charge passing through it is:

Eduardwww [97]

Work is the best answer

6 0

3 years ago

Read 2 more answers

a crude approximation of voice production is to consider the breathing passages and mouth to be a resonating tube closed at one

prohojiy [21]

The fundamental frequency of the tube is 0.240 m long, by taking air temperature to be $37^o$ C is 367.42 Hz.

A standing wave is basically a superposition of two waves propagating opposite to each other having equal amplitude. This is the propagation in a tube.

The fundamental frequency in the tube is given by

$f=\frac{v_T}{4L}$

where, $v_T=v\sqrt{\frac{T}{273} }$

Since, T=37+273 K = 310 K

v = 331 m/s

$\therefore v_T=331\sqrt{\frac{310}{273} } = 352.72 \ m/s$

Using this, we get:

$f=\frac{352.72}{4(0.240)} \\f=367.42 \ Hz$

Hence, the fundamental frequency is 367.42 Hz.

To learn more about Attention here:

brainly.com/question/14673613

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7 0

1 year ago

irius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Ano

Norma-Jean [14]

The actual distance of Regulus from Earth is 23.81 parsecs.

Given:

Parallax of Regulus, p = 0.042 arc seconds

Calculation:

When an observer changes their position, an apparent change in the object's position takes place. This change can be calculated using the angle ( or semi-angle) made by the observer and object i.e. the angle made between the two lines of observation from the object to the observer.

Thus from the relation of parallax of a celestial body we get:

S = 1/ tan p ≈ 1 / p

where S is the actual distance between the object and the observer

p is the parallax angle observed

Here for Regulus, we get:

S = 1 / p

= 1 / (0.042) [ 1 parsecs = 1 arcseconds ]

= 23.81 parsecs

We know that,

1 parsecs = 3.26 light-years = 206,000 AU

Converting the actual distance into light years we get:

23.81 parsecs = 23.81 × (3.26 light yrs) = 77.658 light-years

Therefore, the actual distance of Regulus from Earth is 23.81 parsecs which is 77.658 in light years.

Learn more about astronomical units here:

<u>brainly.com/question/16471213</u>

#SPJ4

6 0

1 year ago