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slavikrds [6]
3 years ago
7

I need help. Can you help me? Thank you

Physics
1 answer:
SashulF [63]3 years ago
7 0
What the ionquestion??
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Parallax error occurs when the observer records data when he/she is at an angle to the event he/she is observing. Where do you t
kompoz [17]

Answer:Orient your line of sight directly above the measurement markings.

Explanation: parallax error is a type of systematic error that occurs when an observer views a measurement marking at a wrong angle. This causes a noticeable disparity in results obtained. Therefore the best way to prevent this error is to view and record the data from the correct angle. This can be obtained by:

-Place the measurement device on its edge so it is level with the object being measured.

-Seek out the finest possible edge of the measurement device, or use a device with finer edges.

In conclusion, ask other observers to also take the reading and get an average of their results. It can help cancel out parallax error results.

4 0
4 years ago
A physical property that describes how something feels<br> Is called?
zubka84 [21]
It's called texture, meaning how something feels.
7 0
3 years ago
Hey, what is antimatter
jenyasd209 [6]
A antimatter is particle physics, antimatter is a material composed of the antiparticle "partners" to the corresponding particles of ordinary matter. A particle and its antiparticle have the same mass as one another, but opposite electric charge and other quantum numbers.
5 0
3 years ago
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A projectile proton with a speed of 500 m/s collides elastically with a target proton initially at rest. The two protons then mo
makkiz [27]

Answer:

(a) The speed of the target proton after the collision is:V_{2f} =433(m/s), and (b) the speed of the projectile proton after the collision is: v_{1f}=250(m/s).

Explanation:

We need to apply at the system the conservation of the linear momentum on both directions x and y, and we get for the x axle:m_{1} v_{1i} =m_{1} v_{1f}Cos\beta _{1} +m_{2} v_{2f}Cos\beta _{2}, and y axle:0=m_{1} v_{1f}Sin\beta _{1}+m_{2} v_{2f}Sin\beta _{2}. Now replacing the value given as: v_{1i}=500(m/s), \beta_{1}=+60^{o} for the projectile proton and according to the problem \beta_{1}and\beta_{2} are perpendicular so \beta_{2}=-30^{o}, and assuming that m_{1}=m_{2}, we get for x axle:500=v_{1f}Cos\beta _{1}+ v_{2f}Cos\beta _{2} and y axle: 0=v_{1f}Sin\beta _{1}+v_{2f}Sin\beta _{2}, then solving for v_{2f}, we get:v_{2f}=-v_{1f}\frac{Sin\beta_{1}}{Sin\beta_{2}}= \sqrt{3}v_{1f} and replacing at the first equation we get:500=\frac{1}{2} v_{1f} +\frac{\sqrt{3}}{2} *\sqrt{3}*v_{1f}, now solving for v_{1f}, we can find the speed of the projectile proton after the collision as:v_{1f}=250(m/s) and v_{2f}=\sqrt{3}*v_{1f}=433(m/s), that is the speed of the target proton after the collision.

5 0
3 years ago
Some life forms move so slowly that their movement cannot be detected by normal observation. The best way to determine any movem
romanna [79]
Not sure the precise concept of "normal observation", but I assume that is observed by "eyes".

Eye observation is basically macroscopic, but when you use a mark, which can be regarded as a point of mass, then it goes to microscopic.

Mark is a reference point which you can compare the relative position change, but with your eyes, first you cannot notice microscopic changes, second the eyes cannot precisely set a stable reference point.
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3 years ago
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