A) F1/A1=F2/A2
F2 = 12000 Newtons, while F1 = 400 Newtons and area A1= 6 cm²
400/6 = 12000/A2
A2 = (6 × 12000)/400
= 180 cm²
b) How long does this lift the car
d2 =F1/F2×d1
= (400/12000)× 20
= (1/30)×20
= 20/30
= 0.67 cm
This lifts the car a distance of 0.67 cm
Friction is a force that acts in a direction opposite to motion. If there were not force of friction, a baseball player would never stop and would be continuously moving in the direction of motion. Balanced forces do not cause a nonmoving object to start moving.
<span>equal-arm balance = 12 kg
spring scale = 2 kg
The equal arm balance measures the mass of an object by using a counter mass on the opposite plate of the balance. The force of gravity affects both the mass being tested and the mass standards being compared against equally. So if the local gravitational field changes, those changes affect both the tested mass and the standard masses equally.
Contrast that to the spring scale. In that scale, the spring provides a calibrated level of force irrespective of the local gravitational field. So if the local gravity is higher, the force indicated also is higher. And if the gravitational field is lower, the indicated force is also lower. The strength of the spring DOES NOT CHANGE with changes in the local gravitational field.</span>
Explanation:
<em><u>Principle of Floatation</u></em>
Principle of Floatation states that weight of floating body is equal to weight of water displaced by it
