All categories

3 years ago

Which values of x make the inequality 1 + 5 x < −9 true?

Mathematics

2 answers:

Kazeer [188]3 years ago

8 0

The answer is x is less than -2

Charra [1.4K]3 years ago

7 0

Answer:

x<-2

Step-by-step explanation:

You might be interested in

The slope of a given line is shown below. Find the slope of a line parallel to the given line and the slope of a line perpendicu

Sphinxa [80]

Answer:

The slope of a line parallel to the given line = 5

The slope of a line perpendicular to the given line = - 1/5

Step-by-step explanation:

6 0

2 years ago

5 (5x6)+(8x9)+6=? 2(5x8)+(8x28)+9

KonstantinChe [14]

Answer:

The left side (228)does not equal the right side(313) that means the given statement is false

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

This figure is made up of a quadrilateral and a semicircle.

Arturiano [62]

Answer:

The correct option is B. The area of the figure is 40.4 units².

Step-by-step explanation:

The line AB divides the figure in two parts one is a rectangle and another is semicircle.

The distance formula is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The length of AB is

$AB=\sqrt{(2+3)^2+(4-2)^2}=\sqrt{25+4}=\sqrt{29}$

The length of AD is

$AD=\sqrt{(-1+3)^2+(-3-2)^2}=\sqrt{4+25}=\sqrt{29}$

Since AB=AD, therefore ABCD is a square. The area of the of square is

$A_1=a\times a=\sqrt{29}\times \sqrt{29} =29$

The area of square is 29 units².

The area of a semicircle is

$A_2=\frac{\pi}{2}r^2$

Since AB is the diameter of the semicircle, therefore the radius of the semicircle is

$r=\frac{d}{2}=\frac{\sqrt{29}}{2}$

The area of the semicircle is

$A_2=\frac{3.14}{2}(\frac{\sqrt{29}}{2})^2=40.3825$

The area of the figure is

$A=A_1+A_2=29+11.2825=40.3825\approx 40.4$

Therefore the area of the figure is 40.4 units². Option B is correct.

5 0

3 years ago

Kelly works at her own nail

Sergeeva-Olga [200]

Answer:

(x×11)÷52.25

Step-by-step explanation:

if 11=52.25 and y=x then x11÷52.25 i think that is the answer

6 0

2 years ago

Solve the following equation: |7 – (24 ÷ | 3-6 |)|<br>(A)15(B)-12(C)1(D)-1

Zepler [3.9K]

PEDMAS

The rule is Paranthesis First

|7-(24÷|3-6|)|

|7-(24÷|-3|)|

Now we have to get the -3 outside the 2 Lines but the lines are saying that if the number inside is negative when you get it outside it has to be positive.

|7-(24÷3)|-

|7-(8)|

|7-8|

|-1|

= 1

3 0

3 years ago

Read 2 more answers