1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tema [17]
3 years ago
5

To play a game, you spin a spinner like the one shown. You win if the arrow lands in one of the areas marked "WIN". Lee played t

his game many times and recorded her results. She won 8 times and lost 40 times. Use Lee's data to explain how to find the experimental probability of winning this game.

Mathematics
2 answers:
Flauer [41]3 years ago
8 0

Answer: \dfrac{1}{6}

Step-by-step explanation:

Given: The number of times Lee won the game = 8

The number of times lee lost the game = 40

Then , the total number of times, she played the game=40+8=48

Now, the experimental probability of winning this game is given by :-

\text{P(win)}=\dfrac{\text{Number of wins}}{\text{Total number of games}}\\\\\RIghtarrow\text{P(win)}=\dfrac{8}{48}=\dfrac{1}{6}

Hence, the experimental probability of winning this game = \dfrac{1}{6}

Mrac [35]3 years ago
6 0
The data collected from the actual game experiment is:

Win: 8 times
Lose: 40 times
Total trials: 48 times

Therefore, the probability that you will win when you play this game is:

WIN = 8/48
        = 1/6 or 0.1667 = 16.67% chance of winning

LOSE = 40/48
           = 5/6 or 0.8333 = 83.33% chance of losing. 
<span />
You might be interested in
!solve this!<br> 3x + 70 − 7x ≥ 18
UNO [17]

Answer:

3x + 70 − 7x ≥ 18

Step 1: Simplify both sides of the inequality.

−4x + 70 ≥ 18

Step 2: Subtract 70 from both sides.

−4x + 70 − 70 ≥ 18 − 70

−4x ≥ −52

Step 3: Divide both sides by -4.

−4x /−4  ≥  −52 /−4

x ≤ 13

8 0
2 years ago
Original price of $52 after a 20% discount
Neporo4naja [7]

Answer:

The new price is 41.60

Step-by-step explanation:

First find the discount

52 * 20%

52 * .2

10.4

Subtract this from 52

52 - 10.4

41.6

The new price is 41.60

5 0
2 years ago
Read 2 more answers
In a multiple choice quiz there are 5 questions and 4 choices for each question (a, b, c, d). Robin has not studied for the quiz
Ahat [919]

Answer:

a) There is a 18.75% probability that the first question that she gets right is the second question.

b) There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

c) There is a 10.35% probability that she gets the majority of the questions right.

Step-by-step explanation:

Each question can have two outcomes. Either it is right, or it is wrong. So, for b) and c), we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem we have that:

Each question has 4 choices. So for each question, Robin has a \frac{1}{4} = 0.25 probability of getting ir right. So \pi = 0.25. There are five questions, so n = 5.

(a) What is the probability that the first question she gets right is the second question?

There is a 75% probability of getting the first question wrong and there is a 25% probability of getting the second question right. These probabilities are independent.

So

P = 0.75(0.25) = 0.1875

There is a 18.75% probability that the first question that she gets right is the second question.

(b) What is the probability that she gets exactly 1 or exactly 2 questions right?

This is: P = P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 1) = C_{5,1}.(0.25)^{1}.(0.75)^{4} = 0.3955

P(X = 2) = C_{5,2}.(0.25)^{2}.(0.75)^{3} = 0.2637

P = P(X = 1) + P(X = 2) = 0.3955 + 0.2637 = 0.6592

There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

(c) What is the probability that she gets the majority of the questions right?

That is the probability that she gets 3, 4 or 5 questions right.

P = P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 3) = C_{5,3}.(0.25)^{3}.(0.75)^{2} = 0.0879

P(X = 4) = C_{5,4}.(0.25)^{4}.(0.75)^{1} = 0.0146

P(X = 5) = C_{5,5}.(0.25)^{5}.(0.75)^{0} = 0.001

P = P(X = 3) + P(X = 4) + P(X = 5) = 0.0879 + 0.0146 + 0.001 = 0.1035

There is a 10.35% probability that she gets the majority of the questions right.

6 0
3 years ago
Is the relation a function?
Margaret [11]
No; a domain value has two range values.

x = -2 then y = 1 and 2

they would form a vertical line, which tells us that it's not a function
8 0
3 years ago
0.05555555555 as a simplified fraction. Please, I’m raging so much right now.
Artemon [7]

Answer:

5555555555/100000000000

Step-by-step explanation:

I guess I am not sure though.

Can you help me with my question?

PLS HELP ASAP!!!!

A restaurant wants to study how well it's salads sell. the circle graph shows the sales over the past few days. If 15 of the salads sold were caesar salads, how many total salads did the restaurant sell Caesar 30% Garden 58% Cobb 12%?

5 0
3 years ago
Read 2 more answers
Other questions:
  • 4(x+1)=16 HELP MEEEEEE
    12·2 answers
  • HELP!! please I can't figure this out​
    11·1 answer
  • Slove for x 2m-nx=x+4
    6·1 answer
  • Mrs. Powers spent $83.25 for gift bags for each of her 21 students. About how much did Mrs. Powers spend on each gift bag? (roun
    15·1 answer
  • Find the sum in simplest form. 10 3/5 + 2 3/5
    10·1 answer
  • How do I solve the equation 16.7-3.5t= 17.12
    13·1 answer
  • Write the number for eight million sixty thousand
    7·1 answer
  • K/2 + 3 =0<br> Show work please
    10·1 answer
  • 1<br> abc14<br> determine whether each expression is a monomial
    5·1 answer
  • If m ∆ n means m²-2mm+n³, determine the value of 3∆2.​
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!