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3 years ago

11

A chain saw requires 7 hours of assembly and a wood chipper 3 hours. a maximum of 63 hours of assembly time is available. the pr

ofit is $170 on a chain saw and $210 on a chipper. how many of each should be assembled for maximum profit?

1 answer:

Evgesh-ka [11]3 years ago

3 0

21 wood chippers should be assembled got maximum profit

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8,2

Step-by-step explanation:

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2 years ago

What is the perimiter, in feet, of a square whose area is 121 square feet

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Square needs to have all equal sides and length and width are the same.

So sqrt the area.

sqrt 121 = 11

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So

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3 years ago

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3 years ago

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3 years ago

Use the standard norml distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justif

dalvyx [7]

Answer:

E) we will use t- distribution because is un-known,n<30

the confidence interval is (0.0338,0.0392)

Step-by-step explanation:

<u>Step:-1</u>

Given sample size is n = 23<30 mortgage institutions

The mean interest rate 'x' = 0.0365

The standard deviation 'S' = 0.0046

the degree of freedom = n-1 = 23-1=22

99% of confidence intervals $t_{0.01} =2.82$ (from tabulated value).

$The mean value = 0.0365$

$x±t_{0.01} \frac{S}{\sqrt{n-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{23-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{22} }$

$0.0365±2.82 \frac{0.0046}{4.690 }$

using calculator

$0.0365±0.00276$

Confidence interval is

$(0.0365-0.00276,0.0365+0.00276)$

$(0.0338,0.0392)$

the mean value is lies between in this confidence interval

(0.0338,0.0392).

<u>Answer:-</u>

<u>using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.</u>

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3 years ago