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3 years ago

Find the average of each of the following.

Mathematics

2 answers:

motikmotik3 years ago

4 0

Step-by-step explanation:

I HAVE DONE AT HERE YOU HAVE ASK WHE\E *O PUT 120°

raketka [301]3 years ago

3 0

Answer:

555

Step-by-step explanation:

(357+452+589+602+775)/5

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314,207 in standard form expanded form and word form

Gennadij [26K]

Three hundred fourteen thousand two hundread seven

Hope it helps!!

8 0

3 years ago

Read 2 more answers

TERESA gave away 8 baseball cards and has 4 BASEBALL cards left. WRITE A subtraction problem tp show the fraction of he baseball

N76 [4]

Teresa gave away 8 baseball cards and has 4 left. 8 plus 4 means she originally had 12. Right now she has 4 out of her original 12 cards remaining. This gives us 4/12. We can simplify this by dividing our greatest common factors. 4 goes into both parts of our fraction, when we divide each part by 4 we end up with 1/3. Since we are unable to simplify this problem any further, this means our solution and fraction is 4/12 aka 1/3.

4 0

3 years ago

Write an inequality for the given statement: The sum of –18 and a number is more than 22.

tia_tia [17]

Let that number be 'x'

So the inequality will be
- 18 + x > 22

or x - 18 > 22

Hope This Helps You!

7 0

3 years ago

Suppose a professional golfing association requires that the standard deviation of the diameter of a golf ball be less than 0.00

Bingel [31]

Answer:

We conclude that the standard deviation of the diameter of a golf ball is less than 0.005 inch.

Step-by-step explanation:

We are given that a professional golfing association requires that the standard deviation of the diameter of a golf ball be less than 0.005 inch.

Assume that the population is normally distributed: 1.678, 1.681, 1.676, 1.684, 1.676, 1.679, 1.681, 1.681, 1.677, 1.676, 1.681, 1.683.

Let $\sigma$ = population standard deviation of the diameter of a golf ball.

SO, Null Hypothesis, $H_0$ : $\sigma \geq$ 0.005 inch {means that the standard deviation of the diameter of a golf ball is more than or equal to 0.005 inch}

Alternate Hypothesis, $H_0$ : $\sigma$ < 0.005 inch {means that the standard deviation of the diameter of a golf ball is less than 0.005 inch}

The test statistics that would be used here One-sample Chi-square test statistics;

T.S. = $\frac{(n-1)s^{2} }{{\sigma^{2} }}$ ~ $\chi^{2} __n_-_1$

where, s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 0.00281 inch

n = sample size = 12

So, the test statistics = $\frac{(12-1)\times 0.00281^{2} }{{0.005^{2} }}$ ~ $\chi^{2} __1_1$

= 3.47

The value of chi-square test statistics is 3.47.

Also, the P-value of test statistics is given by the following formula;

P-value = P( $\chi^{2} __1_1$ < 3.47) = 0.0182

Since, the P-value of the test statistics is less than the level of significance as 0.0182 < 0.05, so we reject our null hypothesis.

Now, at 0.05 significance level the chi-square table gives critical value of 4.575 at 11 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of chi-square as 3.47 < 4.575, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the standard deviation of the diameter of a golf ball is less than 0.005 inch.

7 0

3 years ago

Jon is in a raft 100m from the base of a 54m cliff. What is the angle of depression from the he top of the cliff to the raft? Le

kvv77 [185]

Answer:

28.4 degrees

Step-by-step explanation:

In the diagram attached

Height of the cliff, AB=54 m

Distance of the raft to the base of the cliff, AC=100m

We want to determine the angle of depression from the top of the cliff to the raft. This is angle OBA.

$\angle OBA = \angle BAC $ (Alternate Angles)\\Therefore, in the right triangle ABC\\\tan A =\dfrac{BC}{AC}\\ \tan A =\dfrac{54}{100}\\\tan A =0.54\\A=\arctan 0.54\\A=28.4^\circ$ (to the nearest tenth)$

The angle of depression from the top of the cliff to the raft is 28.4 degrees correct to the nearest tenth.

5 0

3 years ago