Hello!
To solve algebraic equations, we need to use SADMEP. SADMEP is an acronym used only solve for x in algebraic equations. SADMEP is expanded to be: subtraction, addition, division, multiplication, exponents, and parentheses.
(a) 4 + 2(-1) = 10 + 2 (multiply)
4 + -2 = 10 + 2 (add)
2 = 12
This equation has no solutions because <u>2 is never equal to 12</u>.
(b) 30 = 10 - (6 + 10) (simplify the parentheses)
30 = 10 + -1(16) (multiply)
30 = 10 - 16 (simplify)
30 = -6
This equation has no solutions because<u> 30 and -6 is never equal to each other</u>.
(c) 8x = 4x + 4x + 10(x - x)
8x = 4x + 4x + 10(x - x) (simplify [add and subtract])
8x = 8x + 10(0) (multiply)
8x = 8x
This equation has an infinite number of solutions because if you <u>substitute any value into the original equation</u>, <u>both sides of the equation</u> will be <u>always equal</u>.
Answer:
-x+1=2x+3
Step-by-step explanation:
Im not really sure of it but i think thats the answer
Answer:
-36
Step-by-step explanation:
Answer:
97.75 seconds
Step-by-step explanation:
Kong: 15% fewer seconds than Nolan
Nolan: Kong x 115%
Kong x 115%
=85 x 115%
=97.75
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Hope this helps!!!</em></u></h3><h3><u><em>
:) (:</em></u></h3>
Answer:
The probability P of a day with no perceptible earthquakes is 0.0821.
Step-by-step explanation:
We will consider that earthquakes occurring in a day is a <u>Poisson process</u>. The following Poisson probability distribution formula will be used in this question.
<u>p(x,λ) = [e^-λ (λ)ˣ]/x!</u>
where x = number of outcomes occurring
λ = mean number of occurrences
(a) So, in this question we have λ = 2.5 and we need to find the probability that x=0 (no perceptible earthquakes in a day). So,
P(X=0) = p(0,2.5) = [(e^-2.5)(2.5)⁰]/0!
= ((0.0821)*1)/1
P(X=0) = 0.0821
The probability P of a day with no perceptible earthquakes is 0.0821.