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WINSTONCH [101]
4 years ago
13

Which expression is equivalent to 10a + 6?

Mathematics
2 answers:
victus00 [196]4 years ago
8 0
There are a number of expressions that are equivalent to 10a+6.
To find them, you simply have to list the multiples of both 10 and 6.
10- 10 20 30 40 50 60 70 80 90 100
6- 6 12 18 24 30 36 42 48 54 60.
Then, when you multiply the fraction by anything, whether this is 2, 3 or 10, you just have to do this to both parts. 
All of the following expressions are equivalent to 10a+6
20a+12, 30a+18, 40a+24, 50a+30, 60a+36, 70a+42, 80a+48, 90a+54, 100a+60

Or, if you're looking to simplfy, then you have to find a common multiple, which is 2. Therefore, 2 goes outside of the bracket, and you then have to divide 10 by 2 to find out what goes inside the brack. 10a/2= 5a. 6/2=3, therefore, in a bracket, it becomes 2(5a+3)

Hope this helps :) 

Mekhanik [1.2K]4 years ago
6 0
2(5a+3)

Hope this helps!!

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Solve <br> 28 - K _&gt; 7(K - 4)
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Answer:

Solving the inequality 28-K\geq 7(K-4), we get \mathbf{K\leq 7}

Step-by-step explanation:

We need to solve the inequality 28-K\geq 7(K-4)

Using the BODMAS rule, first we will solve the bracket:

28-K\geq 7(K-4)\\28-K\geq 7K-28

Now, we will subtract 28 from both sides

28-K-28\geq 7K-28-28\\-K\geq 7K-56

Subtracting -7k on both sides

-K-7K\geq 7K-56-7K\\-8k\geq -56

Finally, divide both sides by -8 and inverse the inequality, as we are dividing with a minus digit.

\frac{-8K}{-8}\leq \frac{-56}{-8}\\K\leq 7

So, solving the inequality 28-K\geq 7(K-4) we get \mathbf{K\leq 7}

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3 years ago
What is the slope and the point of y - 5 = 3/2 (x + 3)? please help
goldfiish [28.3K]

y - 5 = 3/2(x + 3)

y - 5 = 3/2x + 9/2

y = 3/2x + 9/2 + 5

y = 3/2x + 19/2

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3 years ago
Can someone help me please
svp [43]
I can help you with something else ??
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Select the four points that appear on the line with the given slope and y-intercept
zysi [14]
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3 years ago
Use the discriminant to describe the roots of each equation. Then select the best description.
IrinaK [193]
\frac{-b+- \sqrt{b^{2} -4ac }  }{2a}
This is the solution of the equation, where a=1, b=-5, c=7

So the discriminant is : 
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The square root of -3 is non-real, this both solutions are non-real. 
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3 years ago
Read 2 more answers
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