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Ira Lisetskai [31]
3 years ago
13

What is the distance between (-6,-2) and (0,-8)

Mathematics
2 answers:
Vesnalui [34]3 years ago
5 0
Distance\ Formula \\  \sqrt{(y2-y1)^{2}+(x2-x1)^{2}} \\  \\  \sqrt{(-2-(-8))^{2}+(-6-0)^{2}}   \\  \\  \sqrt{(6)^{2}+(-6)^{2}} \\  \\  \sqrt{36+36}= \sqrt{72} \\  \\  \sqrt{9*8}= 3\sqrt{8}=3 \sqrt{4*2}=6 \sqrt{2} \\  \\ \boxed{6 \sqrt{2} }
mariarad [96]3 years ago
3 0
You can use the distance formula for this. √(x-x)² + (y-y)²

So, √(0 + 6) + (-8 +2)
     =√(6)² + (-6)²
     =√36 + 36
     =√72
     =6√2

So, the distance between those points is 6√2 units.
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Step-by-step explanation:

We use the Venn diagram to calculate the desired probabilities.

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Then note that in the region representing the intercept of A and B there are two possible values.

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P(A | B)=\frac{P(A \ and\ B)}{P(B)}\\\\P(A | B)=\frac{\frac{1}{3}}{\frac{1}{2}}\\\\P(A|B)=\frac{2}{3}

P(A)*P(B)=\frac{2}{3}*\frac{1}{2}=\frac{1}{3}

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