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LuckyWell [14K]
2 years ago
9

Work out the size of angle a and angle b

Mathematics
1 answer:
klemol [59]2 years ago
5 0

Answer:

a = 120°

b = 60°

Step-by-step explanation:

Angle a and 60° are suplementary. The sum of supplementary angles is 180° (straight angle).

a + 60° = 180°

a = 180° - 60°

a = 120°

The sum of angles in the quadrilateral is 360°. Notice how two of the angles in the quadrilateral are marked as right angles (angles marked with a square). Each of them is 90°.

b + 90° + a + 90° = 360°

Substitute a with the value calculated in the previous step.

b + 90° + 120° + 90° = 360°

Solve for b.

b + 300° = 360°

b = 60°

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1) solve for w: 3w - 10 = 4w + 5<br> 2) solve for t:6 -2t &gt;18
Gre4nikov [31]
Problem # 1
 3w-10=4w+5
(3w-10) + (10-4w) = (4w+5) + (10-4w)
(3w-10) + (-4w+10) = (4w+5) + (-4w +10)
3w-10-4w+10 = 4w +5 -4w +10
3w-4w=15
-w=15
w= -15 (w is negative 15)

problem #2.
6-2t > 18
6-2t-6 > 18-6
-2t > 12 
(-1) (-2t) >  12 (-1)
2t > -12
next divide by 2
2t/2 > -12/2
 t >  -6     (t is greater then negative 6)

 
5 0
4 years ago
Evaluate 1/8 + 3/4 Fhffh
kati45 [8]

Answer:

7/8

Step-by-step explanation:

1/8 + 3/4

1/8 +(3x2/4x2)

1/8 + 6/8

7/8

6 0
3 years ago
Read 2 more answers
The formula W = Fd shows the relationship between work, force, and distance solve this formula for distance
Vera_Pavlovna [14]

Answer:

The choose first. d= w/F

Step-by-step explanation:

w = fd \\ \\  d =  \frac{w}{f}

I hope I helped you^_^

5 0
3 years ago
I have $225.00 in my account. I can spend al but 20% of that on some new equipment. What is the most that I can afford to spend
Setler79 [48]
You can "spend all but 20%" so that means you can spend up to 80% of your money (since 20%+80% = 100%). Apply 80% to the value 225

80% of 225 = (80/100)*225 = 0.80*225 = 180

The most you can afford to spend is $180
3 0
4 years ago
Two cars left the city for a suburb, 480 km away, at the same time. The speed of one of the cars was 20 km/hour greater than the
zlopas [31]

Answer:

  • <u>80km/h and 60km/h</u>

Explanation:

<u>1. Data:</u>

i) Distance traveled by the cars:

  • d = 780 km

ii) Speed of the cars:

  • v₁ and v₂
  • v₁ = v₂ + 20 km/h

iii) Time to arrive at the suburb:

  • t₂ - t₁ = 2 hour ⇒ t₂ = t₁ + 2

<u>2. Equations:</u>

  • speed = distance / time

        time  = distance / speed

  • t₂ = 480 / v₂
  • t₁ = 480 / v₁ = 480 / (v₂ + 20)

               t₂        -       t₁                =  2 hour

               ↓                 ↓                    ↓

           480/v₂    -  480/ (v₂ + 20) =  2

             

<u>3. Solve the equation</u>

     480(v₂ + 20) - 480(v₂) =  2 × (v₂ + 20) (v₂)

     240(v₂ + 20) - 240(v₂) =  (v₂ + 20) (v₂)

     240v₂ + 4800 - 240v₂ =  (v₂)²  + 20v₂

      (v₂)²  + 20v₂ - 4800 = 0

      (v₂ + 80) (v₂ - 60) = 0

      v₂ = - 80

      v₂ = 60

Only the positive solution has physical meaning:

  • v₂ = 60km/h                                      ← answer
  • v₁ = 60km/h + 20km/h = 80km/h     ← answer
5 0
3 years ago
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