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2 answers:
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Answer:
34 + 8n
Step-by-step explanation:
a₁ = 42
a₂ = a₁ + 8 = 42 + 8 = 50
a₃ = a₂ + 8 = 50 + 8 = 58
a₄ = a₃ + 8 = 58 + 8 = 66
Arithmetic sequence: 42, 50 , 58 , 66, ......
a₁ = 42 ; d = 8
= a₁ + d(n-1)
= 42 + 8(n - 1)
= 42 + 8n - 8
= 34 + 8n
Answer:
Heights of 29.5 and below could be a problem.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.
This means that
There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.
Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus
Heights of 29.5 and below could be a problem.