<h2>8.6736174e+41 is going to be your answer hope it not to late for your question</h2>
In 7 divided by 3 the divisor would be the number 3.
Answer: ![6\sqrt{2}-30\sqrt{3}](https://tex.z-dn.net/?f=6%5Csqrt%7B2%7D-30%5Csqrt%7B3%7D)
Step-by-step explanation:
Remember that:
![(\sqrt{a})(\sqrt{b})=\sqrt{ab}](https://tex.z-dn.net/?f=%28%5Csqrt%7Ba%7D%29%28%5Csqrt%7Bb%7D%29%3D%5Csqrt%7Bab%7D)
![\sqrt[n]{a^n}=a](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da)
Given the following expression:
![(2-5\sqrt{6})(3\sqrt{2})](https://tex.z-dn.net/?f=%282-5%5Csqrt%7B6%7D%29%283%5Csqrt%7B2%7D%29)
The steps to simplify this expression, are:
1. Apply the Distributive property:
![=(2)(3\sqrt{2})-(5\sqrt{6})(3\sqrt{2})=6\sqrt{2}-15\sqrt{12}](https://tex.z-dn.net/?f=%3D%282%29%283%5Csqrt%7B2%7D%29-%285%5Csqrt%7B6%7D%29%283%5Csqrt%7B2%7D%29%3D6%5Csqrt%7B2%7D-15%5Csqrt%7B12%7D)
2.Since:
![12=2*2*3=2^2*3](https://tex.z-dn.net/?f=12%3D2%2A2%2A3%3D2%5E2%2A3)
You can rewrite the radicand 12 in this form:
![=6\sqrt{2}-15\sqrt{2^2*3}](https://tex.z-dn.net/?f=%3D6%5Csqrt%7B2%7D-15%5Csqrt%7B2%5E2%2A3%7D)
3. Simplifying, you get:
![=6\sqrt{2}-(15)(2)\sqrt{3}=6\sqrt{2}-30\sqrt{3}](https://tex.z-dn.net/?f=%3D6%5Csqrt%7B2%7D-%2815%29%282%29%5Csqrt%7B3%7D%3D6%5Csqrt%7B2%7D-30%5Csqrt%7B3%7D)
4. Notice that the indices of the Radicals are the same, but the radicands don't, then, you can subtract the Radicals.
It would be: 2 × x + 4 + 2× x
= 2x + 4 + 2x
= 4x + 4
In short, Your Final Answer is 4x+4
Hope this helps!