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3 years ago

Find the mean absolute deviation (MAD) of the data in the pictograph below

Mathematics

2 answers:

Julli [10]3 years ago

7 0

Answer:

Step-by-step explanation:

1. find the mean of the values

2. see how much the values surpass or is below the mean (subtract the actual value to the mean *the number has to remain positive saying it must be the absolute value

3.Add the numbers calculated earlier and divie it by the number of values there is (in this case it is 4 glenda,sprinkle,godmother,and rose bud) and u have he answer

mezya [45]3 years ago

4 0

Answer:

Step-by-step explanation:

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A distribution has a mean of 70.If 5 points are added to each individual score, the new mean would be

algol [13]

Answer:

well its free

Step-by-step explanation:

asdasdasdasd

3 0

2 years ago

During optimal conditions, the rate of change of the population of a certain organism is proportional to the population at time

Lana71 [14]

Answer:

The population is of 500 after 10.22 hours.

Step-by-step explanation:

The rate of change of the population of a certain organism is proportional to the population at time t, in hours.

This means that the population can be modeled by the following differential equation:

$\frac{dP}{dt} = Pr$

In which r is the growth rate.

Solving by separation of variables, then integrating both sides, we have that:

$\frac{dP}{P} = r dt$

$\int \frac{dP}{P} = \int r dt$

$\ln{P} = rt + K$

Applying the exponential to both sides:

$P(t) = Ke^{rt}$

In which K is the initial population.

At time t = 0 hours, the population is 300.

This means that K = 300. So

$P(t) = 300e^{rt}$

At time t = 24 hours, the population is 1000.

This means that P(24) = 1000. We use this to find the growth rate. So

$P(t) = 300e^{rt}$

$1000 = 300e^{24r}$

$e^{24r} = \frac{1000}{300}$

$e^{24r} = \frac{10}{3}$

$\ln{e^{24r}} = \ln{\frac{10}{3}}$

$24r = \ln{\frac{10}{3}}$

$r = \frac{\ln{\frac{10}{3}}}{24}$

$r = 0.05$

$P(t) = 300e^{0.05t}$

At what time t is the population 500?

This is t for which P(t) = 500. So

$P(t) = 300e^{0.05t}$

$500 = 300e^{0.05t}$

$e^{0.05t} = \frac{500}{300}$

$e^{0.05t} = \frac{5}{3}$

$\ln{e^{0.05t}} = \ln{\frac{5}{3}}$

$0.05t = \ln{\frac{5}{3}}$

$t = \frac{\ln{\frac{5}{3}}}{0.05}$

$t = 10.22$

The population is of 500 after 10.22 hours.

7 0

2 years ago

Write the equation -3x + 4y = 16 in slope-intercept form.

Vlad1618 [11]

Answer:

y = $\frac{3}{4}$ x + 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c

Given

- 3x + 4y = 16 ( add 3x to both sides )

4y = 3x + 16 ( divide all terms by 4 )

y = $\frac{3}{4}$ x + 4 ← in slope- intercept form

4 0

3 years ago

Read 2 more answers

Draw to show how you can use models to compare a 345 and 391

natali 33 [55]

345= 3 hundreds, 4 tens, and 5 ones
391= 3 hundreds, 9 tens, and 1 one
You can use the model I attached to help u see it better.
Hope this helps!

6 0

3 years ago

Simplify the expression. (16y54y3)12 Enter your answer in the box.

sp2606 [1]

Answer:

Simplify the expression: $(16y^{\frac{5}{4}}y^3)^{\frac{1}{2}}$

Use the exponent power:

$a^n \cdot a^m = a^{n+m}$

$\sqrt[n]{a^n} =a$
$(a^n)^m = a^{nm}$

$(16y^{\frac{5}{4}}y^3)^{\frac{1}{2}}$

Apply the given rules;

$(16y^{\frac{5}{4} +3} )^{\frac{1}{2}}$

Simplify:

$(16y^{\frac{17}{4}} )^{\frac{1}{2}}$

then;

$(16)^{\frac{1}{2}} \cdot (y^{\frac{17}{4}})^{\frac{1}{2}} = 4y^{\frac{17}{8}}$

Therefore, the simplified expression of $(16y^{\frac{5}{4}}y^3)^{\frac{1}{2}}$ is, $4y^{\frac{17}{8}}$

7 0

3 years ago