Answer:
7,272.7m
Explanation:
Our knowns:
a = 5.2m/s^2
t = 32.8s
= 0 m/s
Our Unknowns:
Distance (x): ?
We can use displacement formula:
ΔX = t + 
a 
Plug in knowns:
X = 0 + 1/2 ((5.2)(32.8))^2
Answer:
ΔX = 7272.7m
(I beleive this should be right) let me know if it helped!
Answer:
Speed will be: 1.33ft/s
Explanation:
If ladder is 10 ft long and bottom is 8 ft from the wall then by Pythagoras theorem we can find the height of the wall where ladder touches. (before it started slipping)
thus 
Giving x= 6 ft. If the ladder is falling with a speed of 4ft/s it will take 1.5 seconds to cover the 6ft distance.
This shows that the bottom of ladder will travel from 8ft to 10 ft in 1.5 seconds. Thus covering 2 ft in 1.5 seconds making the speed to be:
v = S / t
v = 2 / 1.5
v = 1.33 ft/s
Make sure to thank me
The answers are by:
Investigation
Sampling
Repetition
Blind Studies
Out of the following given choices;
a. decelerate; accelerate
b. accelerate; decelerate
c. stop; accelerate
d. decelerate; stop
<span>The answer is B. This is because
the cold front usually rotates around the warm front as cold air mass coverage
in the low-pressure system. This causes the cold air mass to accelerate to
catch up with the warm front. When an occluded front ( that is the boundary
that separates the older cool air mass already in place from new incoming cold
air mass), that the system decelerates. </span>
a.) K 2=K 1 +GmM( r 21− r 11)=2.2×10 7J
b.) K 2 +GmM( r 11− r 21)=6.9×10 7 J
Applying Law of Energy conservation :
K 1+U 1
=K 2+U 2
⇒K 1− r 1GmM
=K 2− r 2 GmM
where M=5.0×10 23kg,r1
=> R=3.0×10 6m and m=10kg
(a) If K 1
=5.0×10 7J and r 2
=4.0×10 6 m, then the above equation leads to
K 2=K 1 +GmM (r 21− r 11)=2.2×10 7J
(b) In this case, we require K 2
=0 and r2
=8.0×10 6m, and solve for K 1:K 1
=K 2 +GmM (r 11− r 21)=6.9×10 7 J
Learn more about Kinetic energy on:
brainly.com/question/12337396
#SPJ4
