Answer:
a = 4/9 m/s^2
Explanation:
We use the kinematics formula for distance (d) covered i accelerated motion:
d = vi t + (1/2) a t^2
and replace d= 2, t = 3 and vi = 0 as per the information given:
2 = (1/2) a (3)^2
2 = (1/2) a (9)
a = 4 / 9 m/s^2
Answer:
Because nothing is blocking the LIGHT!
Explanation:
Light may still be shining on the whole glass but if it wasn't there light would shine brighter than if it was there.
When an object falls or is dropped from rest it's initial velocity is zero.
Using the equations for a motion in straight line. I can find the time it takes to reach 3.0 m down (half way).
x = vt - 4.9t²
-3 = 0 - 4.9t²
-3/-4.9 = t²
0.6122 = t²
0.7825 sec = t
v = v - gt
v = 0 - 9.8(0.7825)
v = -7.67 m/s
the negative denotes downward direction.
You could also solve the problem using potential and kinetic energy.
Since it starts with maximum PE and gets converted to KE when it hits the ground. mgh = mv²/2
mass cancels, use 3 meters for the halfway distance
-9.8(-3) = v²/2
29.4 * 2 = v²
√(58.8) = 7.67 m/s downwards
Lighting is the static electricity stored in the clouds that is disposed to the earth.
Answer:
t = 10.1 s
d = 2020 m
Explanation:
Time to drop from vertical rest
h = ½gt²
t = √(2h/g) = √(2(500)/9.8) = 10.1 s
d = vt = 200(10.1) = 2020 m
