Answer:
v' = 2.4 m/s
Explanation:
Given that,
Mass of one skater, m = 60 kg
Mass of the other's skater, m' = 60 kg
The two skaters push off each other. After the push, the smaller skater has a velocity of 3.0 m/s.
When there is no external force acting on a system, the momentum remains conserved. It means initial momentum is equal to the final momentum. Let v' is the velocity of the larger skater.
mv = m'v'
So, the velocity of the larger skater is 2.4 m/s.
1) Gravitational potential energy: 73 500 J
2) Kinetic energy: 135 000 J
3) Mechanical energy: 208 500 J
Explanation:
1)
The gravitational potential energy of an object is the energy possessed by the object due to its position in the Earth's gravitational field, and it is given by
where
m is the mass of the object
is the acceleration of gravity
h is the height of the object relative to the ground
For the skydiver in this problem,
m = 75 kg is his mass
h = 100 m is his height above the Earth
Substituting, we find
2)
The kinetic energy of a body is the energy due to its motion, and it is given by
where
m is the mass of the body
v is its speed
For the skydiver in this problem,
m = 75 kg is his mass
v = 60 m/s is his speed
Substituting, we find the kinetic energy
3)
The mechanical energy of an object is the sum of the gravitational potential energy and the kinetic energy of the object:
where
U is the gravitational potential energy
K is the kinetic energy
For the skydiver in this problem,
U = 73,500 J is the gravitational potential energy
K = 135,000 J is the kinetic energy
Substituting, we find
Learn more about potential energy and kinetic energy:
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