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1 year ago

7

Which factor affects the angle of sunlight on Earth? The distance between Earth and the sun Earth's tilt from its axis The path

of Earth's orbit Earth's speed of rotation

1 answer:

Rainbow [258]1 year ago

6 0

Earth’s tilt from its axis.
For explanation:
The angle in which Earth is at is 23.5°. This causes its tilt which affects how the Sun’s light hits Earth

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Two asteroids collide and stick together. The first asteroid has a mass of 15\times 10^3\,\mathrm{kg}15×10 3 kg and is initially

statuscvo [17]

Answer:

Final speed is 900.06 m/s at $0.2215^{\circ}$

Solution:

As per the question:

Mass of the first asteroid, m = $15\times 10^{3}\kg$

Mass of the second asteroid, m' = $20\times 10^{3}\kg$

Initial velocity of the first asteroid, v = 770 m/s

Initial velocity of the second asteroid, v' = 1020 m/s

Angle between the two initial velocities, $\theta = 20^{\circ}$

Now,

Since, the velocities and hence momentum are vector quantities, then by the triangle law of vector addition of 2 vectors A and B, the resultant is given by:

$\vec{R} = \sqrt{A^{2} + 2ABcos\theta + B^{2}}$

Thus applying vector addition and momentum conservation, the final velocity is given by:

$(m + m')v_{final} = \sqrt{(mv)^{2} + 2(mv)(m'v')cos20^{\circ} + (m'v')^{2}}$ (1)

Now,

$(m +m')v_{final} = (35\times 10^{3})v_{final}$

$(mv)^{2} = (15\times 10^{3}\times 770)^{2} = 1.334\times 10^{14}$

$(m'v')^{2} = (20\times 10^{3}\times 1020)^{2} = 4.16\times 10^{14}$

$2(mv)(m'v')cos20^{\circ} = 2(15\times 10^{3}\times 770)(20\times 10^{3}\times 1020)cos20^{\circ} = 4.43\times 10^{14}$

Now, substituting the suitable values in eqn (1), we get:

$v_{final} = 900.06\ m/s$

Now, the direction for the two vectors is given by:

$\theta = sin^{- 1} \frac{m'v'sin20^{\circ}}{(m + m')v_{final}}$

$\theta = sin^{- 1} \frac{20\times 10^{3}\times 1020sin20^{\circ}}{(35\times 10^{3})\times 900.06} = 0.2215^{\circ}$

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3 years ago

Can you ever hold your Moon sphere in the light and have it be more or less than half-lit?

Anettt [7]

No if in the light it would be always half lit

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3 years ago

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Problem: At the local swimming hole, a favorite trick is torun

denis23 [38]

Answer:

2 revolutions

Explanation:

Assume that when she runs off the edge of the 8.3m high cliff, her vertical speed is 0. So gravitational acceleration g = 9.8m/s2 is the only thing that makes her fall down. So we can use the following equation of motion to calculate the time it takes for her to fall down:

$s = gt^2/2$

where s = 8.3 m is the distance that she falls, t is the time it takes to fall, which is what we are looking for

$t^2 = \frac{2s}{g} = \frac{2*8.3}{9.8} = 1.694$

$t = \sqrt{1.694} = 1.3 s$

Since she rotates with an average angular speed of 1.6rev/s. The number of revolutions she would make within 1.3s is

$rev = 1.3 * 1.6 = 2 revolution$

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4 years ago

Which of the following fields push on a stationary electron?(A) electric and gravitational fields but not magnetic fields. (B) g

ruslelena [56]

Answer:

(A) electric and gravitational fields but not magnetic fields.

Explanation:

Let's analyze the effect produced by each of the three fields on the stationary electron:

- Gravitational force: the gravitational force exerted on the electron by a gravitational field is

$F=mg$

where

m is the mass of the electron

g is the strength of the gravitational field

Since the mass of the electron m is non-zero, the electron experiences a gravitational force.

- Electric field: the electric force exerted on the electron by an electric field is

$F=qE$

where

q is the charge of the electron

E is the magnitude of the electric field

Since the charge q of the electron is non-zero, the electron experiences an electric force.

- Magnetic field: the magnetic force exerted on the electron by a magnetic field is

$F=qvBsin \theta$

where

q is the electron charge

v is the velocity of the electron

B is the magnitude of the magnetic field

$\theta$ is the angle between the direction of v and B

Since the electron is stationary, we notice that the velocity is zero: v=0, therefore the magnetic force is zero as well.

Therefore, the correct answer is

(A) electric and gravitational fields but not magnetic fields.

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An object is in circular motion with a constant speed of 4 m/s with a radius of 4 m. what is the centripetal acceleration of the

mina [271]

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4 years ago