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Step2247 [10]
2 years ago
7

If the frequency of an FM wave is 8.85 × 10¥ hertz, what is the period of the FM wave?

Physics
2 answers:
larisa [96]2 years ago
7 0
The value of the period of the wave is the reciprocal of its frequency in hertz (1/s). From the given above, the value of the period is calculated below,
                                 t = 1 / f = 1 / (8.85 x 10^7 1/s)
Thus, the value of period (t) is equal to 1.13 x 10^-8 s. The answer is letter B. 
natka813 [3]2 years ago
6 0

for plato users it is 1.10 X 10^-8 just took the test got 100 percent so ik its right

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Suppose, the same angular momentum is transferred to two rotating bodies of different moment of inertia , how will you compare t
Sonbull [250]

Answer:

As per the law of conservation of angular momentum, the angular velocity will be higher for the body with a lower moment of inertia and vice versa.

Explanation:

Angular momentum L of a body is given by:

L=I\times \omega

Now when the same angular momentum is transferred to two different bodies with different moment of inertia, the body with a higher moment of inertia will have lower angular velocity and vice versa.

4 0
3 years ago
____________are necessary to explain research findings.
Elodia [21]

Answer:

C. Theories

Explanation:

Theories basically explain why of research findings. By definition, theories help us understand, explain, and predict the occurrence of a phenomena. In research, theories support research findings by explaining how the variables involved influence each other not merely based on observation during this one experiment. It also helps validate the findings by relating it to theories of previous work.

5 0
3 years ago
In the United States, household electric power is provided at a frequency of 60 HzHz, so electromagnetic radiation at that frequ
grigory [225]

Answer:

the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²

Explanation:

Given the data in the question;

To determine the maximum intensity of an electromagnetic wave, we use the formula;

I = \frac{1}{2}ε₀cE_{max²

where ε₀ is permittivity of free space ( 8.85 × 10⁻¹² C²/N.m² )

c is the speed of light ( 3 × 10⁸ m/s )

E_{max is the maximum magnitude of the electric field

first we calculate the maximum magnitude of the electric field ( E_{max  )

E_{max = 350/f kV/m

given that frequency of 60 Hz, we substitute

E_{max = 350/60 kV/m

E_{max = 5.83333 kV/m

E_{max = 5.83333 kV/m × ( \frac{1000 V/m}{1 kV/m} )

E_{max = 5833.33 N/C

so we substitute all our values into the formula for  intensity of an electromagnetic wave;

I = \frac{1}{2}ε₀cE_{max²

I = \frac{1}{2} × ( 8.85 × 10⁻¹² C²/N.m² ) × ( 3 × 10⁸ m/s ) × ( 5833.33 N/C )²

I = 45 × 10³ W/m²

I = 45 × 10³ W/m² × ( \frac{1 kW/m^2}{10^3W/m^2} )

I = 45 kW/m²

Therefore, the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²

7 0
2 years ago
In a skating stunt known as "crack-the-whip," a number of skaters hold hands and form a straight line. They try to skate so that
4vir4ik [10]

Answer:

The magnitude of the centripetal force that acts on him

Explanation:

Given that,

Mass = 80.0 kg

Distance = 6.10 m

Speed = 6.80 m/s

We need to calculate the magnitude of the centripetal force that acts on him

Using formula of the centripetal force

F_{c}=\dfrac{mv^2}{r}

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m = mass

v = speed

r = distance

Put the value into the formula

F_{c}=\dfrac{80.0\times(6.80)^2}{6.10}

F_{c}=606.4\ N

Hence, The magnitude of the centripetal force that acts on him

7 0
3 years ago
______ is the most abundant gas in Earth’s atmosphere.
algol13

Answer:

<em>Nitrogen</em>

Explanation:

<u>Composition of the Atmosphere</u>

The atmosphere contains several gases, most of them in small amounts, which may include some pollutants and greenhouse gases.

The most abundant gas in the atmosphere is nitrogen (78%), followed by oxygen (21%) as the second. The inert gas called Argon is the third most abundant gas in the atmosphere (less than 1%).

Finally, the fourth most abundant gas in Earth's atmosphere is Carbon dioxide

4 0
2 years ago
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