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Step2247 [10]
3 years ago
7

If the frequency of an FM wave is 8.85 × 10¥ hertz, what is the period of the FM wave?

Physics
2 answers:
larisa [96]3 years ago
7 0
The value of the period of the wave is the reciprocal of its frequency in hertz (1/s). From the given above, the value of the period is calculated below,
                                 t = 1 / f = 1 / (8.85 x 10^7 1/s)
Thus, the value of period (t) is equal to 1.13 x 10^-8 s. The answer is letter B. 
natka813 [3]3 years ago
6 0

for plato users it is 1.10 X 10^-8 just took the test got 100 percent so ik its right

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2 years ago
A roller coaster car starts from rest at the top of a hill 15 m high and rolls down to ground level. From there it starts into a
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Answer:

955.5N

Explanation:

The normal force is given by the difference between the centripetal force and gravity at the top of the loop:

F_N = F_C - F_G = m\frac{v^{2} }{r} - mg

mass m = 65kg

radius of the loop r = 4m

velocity v = ?

g = 9.8 m/s²

To find the centripetal force, you need to find the velocity of the car at the top of the loop.

Use energy conservation:

E_{tot}=mgh + \frac{1}{2} mv^{2}

At the top of the hill:

E_{tot}= mgh_{hill}

At the top of the loop:

E_{tot}=mgh_{loo}_p +\frac{1}{2} m v^{2}

Setting both energies equal and canceling the mass m gives:

gh_{hill} = gh_{loo}_p + \frac{1}{2} v^{2}

Solving for v:

v^{2} = 2g(h_{hill}-h_{loo}_p)

Using v in the first equation:

F_N = \frac{2mg(h_{hill}-h_{loo}_p)}{r} - mg

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7 0
3 years ago
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4 0
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Answer:

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6 0
3 years ago
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4 0
3 years ago
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