Question

an airplane accelerates down a runway at 5.20 m/s^2 for 32.8s until it finally lifts off the ground. determine the distance traveled before takeoff

Answer 1

Answer:

7,272.7m

Explanation:

Our knowns:

a = 5.2m/s^2

t = 32.8s

$V_{i}$ = 0 m/s

Our Unknowns:

Distance (x): ?

We can use displacement formula:

ΔX = $V_{i}$ t + $\frac{1}{2}$ a $t^{2}$

Plug in knowns:

X = 0 + 1/2 ((5.2)(32.8))^2

Answer:

ΔX = 7272.7m

(I beleive this should be right) let me know if it helped!