What’s the domain to the function y=1/3x

1 answer:

6 0

$If\ is\ y=\dfrac{1}{3}x,\ then\ it's\ a\ linear\ function.\ Domain\ is\ the\ set\ of\ all\ real\ numbers.\\\\D=\mathbb{R}\\\\If\ is\ y=\dfrac{1}{3x},\ then\ domain\ is\ the\ set\ of\ all\ real\ number\ except\ 0\\\\D=\mathbb{R}-\{0\}\to x\in(-\infty,\ 0)\ \cup\ (0,\ \infty)$

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Please someone help....

vekshin1

Answer:

Box 1

Step-by-step explanation:

If you look carefully, you will notice that Boxes 2, 3, and 4 are all equations. We know this because they all have the "=" sign. On the other hand, Box 1 is an expression. We know this because it doesn't have an "=" sign. Therefore, Box 1 is the odd one out.

4 0

3 years ago

Read 2 more answers

Gary won $70,000 in the lottery after all tax deductions. He invested part of the money at 11% and deposited the remainder in ta

Paraphin [41]

Let x represent the amount of money he invested at 11% and y money he invested at 12%. Now we write system of equations:

x*1.11 + y*1.12 = 70 000 + 7900
x + y = 70 000

We will multiply second equation with 1.11
x*1.11 + y*1.11 = 77700
and subtract if from first:
0.01*y = 200
y = 20000

x = 70000 - 20000 = 50000

6 0

3 years ago

Simplify the expression. a^-5 b-4/a^-13 b^8

grin007 [14]

Answer:

a^8 ÷ b^12

Step-by-step explanation:

a^-5 · b^-4 / a^-13 · b^8

when dividing exponents with the same bases, subtract the exponents

a^8 · b^-12

do not leave a negative exponent; put it into the denominator and it becomes positive

b^-12 = 1 /b^12

4 0

3 years ago

4. A triangle has vertices A(4, 2), B(3, 7), and C(–4, –5).

Alex

To draw the median of the triangle from vertex A, the mid point of BC must be determined. The median of the vertex A is given at (-1/2, 1). See explanation below.

<h3>How you would draw the median of the triangle from vertex A?</h3>

Recall that B = (3, 7)

and C = (-4, -5).

Note that when you are given coordinates in the format above, B or C = (x, y)
Hence the mid point of line BC is point D₁ which is derived as:
D₁ $[ (\frac{3-4}{2})$ , $(\frac{7-5}{2}) ]$
hence, the Median of the Vertex A = (-1/2, 1).