The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.
<h3>What is the average of five consecutive integers ending with b?</h3>
First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;
(a+a+2+a+4+a+6+a+8+a+10)/6 = b
6b=6a+30
b=a+5
Also, let the average of the consecutive intergers ending with b be denoted by; x.
(b+b-1+b-2+b-3+b-4)/5 = x
=(5b-10)/5
=b–2
The average, x=b – 2 (where b = a-5)
Ultimately, the value of the required average is; = a+5-2 = a+3.
Read more on average of integers;
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The GCF is <span>1. hope that helps</span>
Series = <span>{2, 5 ,6, 7, 15, 16, 17}
Here, Median = 7
Then Q3 = </span><span>{15, 16, 17}
Median of Q3 = 16
In short, Your Answer would be: 16
Hope this helps!</span>
Write tan in terms of sin and cos.
Recall that
Rewrite and expand the given limand as the product
Then using the known limit above, it follows that
Let the length of the shorter sides be x, then
Perimeter = x + x + x + 5
29 = 3x + 5
3x = 29 - 5 = 24
x = 24/3 = 8
Therefore, the length of longest side is 8 + 5 = 13 m.
