3 years ago

Which of the following ordered pairs could be placed in the table and still have the relation qualify as a linear function?

Mathematics

1 answer:

Paul [167]3 years ago

6 0

Your answer will be (7, 3).

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2<img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" alt="\pi" align="absmiddle" class="latex-formula"> x 24 s

Simora [160]

Answer: $48\pi$

Step-by-step explanation:

$(2 \times 24)\pi=48\pi$

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2 years ago

19. 7 * 645 =<br> What does it equal

lutik1710 [3]

Answer:

4515

Step-by-step explanation:

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3 years ago

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Last questions, plz help

Goryan [66]

Answer:

9. $a_n=7+6n$

10. $a_n=a_{n-1}+7$

Step-by-step explanation:

9. Given the sequence

$13, 19, 25, ...$

In this sequence,

$a_1=13\\ \\a_2=19\\ \\a_3=25\\ \\...$

Note that

$a_2-a_1=19-13=6\\ \\a_3-a_2=25-19=6,$

then the common difference in this sequence is $d=6$

You have

$a_1=13\\ \\d=6,$

then the explicit formula is

$a_n=a_1+(n-1)d\\ \\a_n=13+(n-1)\cdot 6\\ \\a_n=13+6n-6\\ \\a_n=7+6n$

10. Given the sequence

$-10,-3, 4, 11, ...$

In this sequence,

$a_1=-10\\ \\a_2=-3\\ \\a_3=4\\ \\a_4=11\\ \\...$

Note that

$a_2-a_1=-10-(-3)=-10+3=-7\\ \\a_3-a_2=-3-4=-7\\ \\a_4-a_3=11-4=7,$

then the common difference in this sequence is $d=7$

You have

$a_1=-10\\ \\d=7,$

then the recursive formula is

$a_n=a_{n-1}+d\\ \\a_n=a_{n-1}+7$

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3 years ago

म़ीरा ने किस को अपऩी जाग़ीर बताया है?class 10

lorasvet [3.4K]

Answer:

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3 years ago

Evaluate this function: For f(x) = -2x + 9, find f(5)

saul85 [17]

f(5) is -1

Step-by-step explanation:

Step 1: Given f(x) = -2x + 9, find f(5)

f(5) = -2 × 5 + 9 = -10 + 9 = -1

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4 years ago

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