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Alex_Xolod [135]
3 years ago
12

7x^4 - 14x^3 - 28x

Mathematics
2 answers:
Whitepunk [10]3 years ago
7 0

Answer:

The greatest common factor is 7x

vesna_86 [32]3 years ago
4 0

Answer:

7x

Step-by-step explanation:

if you divide all of them by 7x, you get

x^3 - 2x^2 - 4

There are no other factors.

The first two have a factor of x, but the last one doesn't

the last two have a factor of 2, but the first one doesn't

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Jen Butler has been pricing​ Speed-Pass train fares for a group trip to New York. Three adults and four children must pay $ 99. 
8090 [49]

Answer:

An adult ticket is 17

A childs ticket costs 12 dollars

Step-by-step explanation:

Let a = adult price

c = child price

3a + 4c = 99

2a + 3c = 70

Multiply the first equation by 2

2(3a + 4c) = 99*2

6a + 8c = 198

Multiply the second equation by -3

-3 (2a + 3c) = 70*-3

-6a -9c = -210

Add these new equations together

6a + 8c = 198

-6a -9c = -210

----------------------

     -c = -12

Multiply by -1

        c = 12

A childs ticket costs 12 dollars

Now we need to find the price of an adult ticket

2a + 3c = 70

2a + 3(12) = 70

2a +36 = 70

Subtract 36 from each side

2a +36-36 =70-36

2a = 34

Divide by 2

2a/2 = 34/2

a = 17

An adult ticket is 17

7 0
3 years ago
Here 2.4,1.6, 3.2,0.3, 1.5 . a)Calculate the means . b)Each piece of data is increased by 10. Calculate the new mean. c) Each ne
vagabundo [1.1K]

Answer:

1.8 ; 11.8 ; 4.18

Step-by-step explanation:

Given the data:

X : 2.4,1.6, 3.2,0.3, 1.5

Mean, m = Σx / n

Σx = 9 ; n = 5

m = 9 /5

m = 1.8

If data is increased by 10:

X : 12.4, 11.6, 13.2, 10.3, 11.5

Σx = 59 ; n = 5

m = 59 /5

m = 11.8

If data values is doubled :

X : 5.76, 2.56, 10.24, 0.09, 2.25

Σx = 20.9 ; n = 5

m = 20.9 /5

m = 4.18

7 0
3 years ago
Recommended daily intake of fiber
Ganezh [65]
25 grams per day that is the recommended daily intake of fiber
4 0
3 years ago
Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally
Dafna1 [17]

Answer:

a) 0.0869 = 8.69% probability that the thickness is less than 3.0 mm

b) 0.0668 = 6.68% probability that the thickness is more than 7.0 mm

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 4.9, \sigma = 1.4

(a) the thickness is less than 3.0 mm

This is the pvalue of Z when X = 3.

Z = \frac{X - \mu}{\sigma}

Z = \frac{3 - 4.9}{1.4}

Z = -1.36

Z = -1.36 has a pvalue of 0.0869

0.0869 = 8.69% probability that the thickness is less than 3.0 mm

(b) the thickness is more than 7.0 mm

This is 1 subtracted by the pvalue of Z when X = 7. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{7 - 4.9}{1.4}

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

1 - 0.9332 = 0.0668

0.0668 = 6.68% probability that the thickness is more than 7.0 mm

5 0
3 years ago
The band club needs $1328 for decorations for this year’s concert. So far, they have $43. Find the minimum amount each of the 30
Mariulka [41]

Answer:

$42.83

Step-by-step explanation:

1: Subtract the amount they have by the amount they need.

1328-43= $1,285.

2: Divide amount they need ($1,285) by the total staff members (30).                Hence the equation is 1285 ÷ 30

3: Whatever answer you get from that equation is the answer

1285 ÷ 30 = $42.83

When you divide, you are setting the amount each staff member needs to donate by seeing how much money 30 people can give (equally) that adds up to 1285.

Hope this helps :)

-jp524

3 0
3 years ago
Read 2 more answers
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