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miss Akunina [59]
3 years ago
6

Calculate. 7.75% of $9,000 = 69,750.00 6,975.00 69.75 697.50

Mathematics
2 answers:
valina [46]3 years ago
4 0

Answer:

 $ 697.50

Step-by-step explanation:

Given: 7.75% of $9,000,

To find : Calculate .

Solution: we have given that  7.75% of $9,000.

  7.75% of $9,000 = \frac{7.75*9000}{100}.

  7.75% of $9,000 =7.75*90.

 7.75% of $9,000 = 697.50.

 7.75% of $9,000 = $ 697.50

Therefore,  $ 697.50

VikaD [51]3 years ago
3 0

Answer:

697.5

Step-by-step explanation:

to find a percent of the number, you take the decimal version of the percent and multiply

7.75% as a decimal is .0775

.0775 * 9000= 697.5


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The sum of two numbers is 70. one number is 4 times as large as the other. What are the numbers?
FinnZ [79.3K]

One number is 4 times the other, so x and 4x.

The sum of two numbers is 4x+x=70.

Solve for x to get

x=70/5=14

the other number is 4x=4*14=56

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3 years ago
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Find the area of a regular octagon with an apothem of 7 inches and a side length of 5.8 inches. (nearest tenth)
Kisachek [45]

Answer:

162.4 in²

Step-by-step explanation:

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Let's start with what we know:

Area of regular octagon = 1/2 x perimeter x apothem

We know the apothem, so all that we need to find to fill in the above equation is the perimeter:

perimeter = 8 x 5.8 = 46.4in

Now we can fill in our original equation and solve:

Area of regular octagon = 1/2 x perimeter x apothem

Formula = n (s/2)² divided by tan( π /n)

   = 8 (5.8/2)²  divided by tan ( π /8)

                 = 162.4283 in²

ORRR when rounded to the nearest tenth,

                      =162.4 in²

6 0
3 years ago
Below are survival times (in days) of 13 guinea pigs that were injected with a bacterial infection in a medical study:
tresset_1 [31]

Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

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Sort the dataset in ascending order

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<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

Q1 = \frac{N +1}{4}th

So, we have:

Q1 = \frac{13 +1}{4}th

Q1 = \frac{14}{4}th

Q1 = 3.5th

This is the average of the 3rd and the 4th element

Q1 = \frac{1}{2} \times (84 + 91)

Q1 = 87.5

<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

Q3 =  3 \times \frac{N +1}{4}th

So, we have:

Q3 =  3 \times \frac{13 +1}{4}th

Q3 =  3 \times 3.5th

Q3 =  10.5th

This is the average of the 10th and the 11th element.

Q_3 =\frac12 \times (98 + 101)

Q_3 =99.5

<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

IQR = Q_3 -Q_1

IQR = 99.5 - 87.5

IQR = 12

Also, we have:

IQR(1.5) = 12 \times 1.5

IQR(1.5) = 18

<h3>The outlier range</h3>

The lower and the upper outlier range are calculated as follows:

Lower = Q_1 - IQR(1.5)

Lower = 87.5- 18

Lower = 69.5

Upper = Q_3 + IQR(1.5)

Upper = 99.5 + 18

Upper = 117.5

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120

Read more about outliers at:

brainly.com/question/9933184

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Answer:

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Step-by-step explanation:

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konstantin123 [22]

Answer:

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x = 7 ± \sqrt{15}

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